Question

A system gains 1500 J of heat, while the internal energy of the system increases by 4500 J and the volume decreases by . Assume that the pressure is constant and find its value.

Answer 1

Answer:

Hence the pressure is $3\times 10^5 Pa$

Explanation:

Given data

Q=1500 J   system gains heat

ΔV=- 0.010 m^3     there is a decrease in volume

ΔU= 4500 J        internal energy decrease

We know work done is

W= Q- ΔU

=1500-4500= -3000 J

The change in the volume at constant pressure is

ΔV= W/P

there fore P = W/ΔV= -3000/-0.01= 3×10^5

Hence the pressure is $3\times 10^5 Pa$