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gtnhenbr [62]
3 years ago
11

g Describe how an electron can possess the properties of both a particle and a wave. How do the wave properties of electrons rel

ate to the Heisenberg uncertainty principle? Electrons possess the properties of particles in that they ---Select--- . However, Louis de Broglie theorized that matter can also show wave properties, specifically characteristic wavelengths based on its mass and velocity. The wave properties of electrons were observed by their ability to ---Select--- when passed through a crystal, similar to the diffraction of electromagnetic waves. The Heisenberg uncertainty principle states that wave properties of electrons ---Select--- the exact location of an electron in space.
Physics
1 answer:
nalin [4]3 years ago
8 0

Answer:

See explanation

Explanation:

According to Louis de Broglie, matter has an associated wavelength. Hence, there exist no clear cut difference between matter and wave. Matter may be regarded as a wave and vice versa depending on the behavior of each under the given circumstances.

According to Heisenberg uncertainty principle, the position and momentum of matter can not be simultaneously determined with precision. This further reinforces the wave-particle concept of the electron.

When electrons are passed through crystals, they are diffracted just like electromagnetic waves. This further reinforces the wave-particle paradox.

According to The Heisenberg uncertainty principle, the wave property of electrons determine their exact location in space

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Suppose you want to design an air bag system that can protect the driver at a speed 100 km/h (60 mph) if the car hits a brick wa
34kurt

When solving question that contains equations and the use mathematical computations, It is always ideal to list the parameters given.

Now, given that:

  • the speed of the car which is the initial velocity (u) = 100 km/h before it hits the wall.
  • after hitting the wall, the final velocity will be (v) = 0 km/h

Assumptions:

  • Suppose we make an assumption that the distance travelled during the collision of the car with the brick wall (S) = 1 m
  • That the car's acceleration is also constant.

∴

For a motion under constant acceleration, we can apply the kinematic equation:

\mathsf{v^2 = u^2 + 2as}

where;

v = final velocity

u = initial velocity

a = acceleration

s = distance

From the above equation, making acceleration (a) the subject of the formula:

\mathsf{v^2 - u^2 =2as }

\mathsf{a = \dfrac{v^2 - u^2 }{2s}}

The initial velocity (u) is given in km/h, and we need to convert it to m/s as it has an effect on the unit of the acceleration.

since 1 km/h = 0.2778 m/s

100 km/h = 27.78 m/s

\mathsf{a = \dfrac{(0)^2 - (27.78)^2 }{2(1)}}

\mathsf{a = \dfrac{- 771.7284 }{2}}

a = - 385.86 m/s²

Similarly, from the kinematic equation of motion, the formula showing the relation between time, acceleration and velocity is;

v = u + at

where;

v = 0

-u = at

\mathsf{t = \dfrac{-u}{a}}

\mathsf{t = \dfrac{-27.78}{-385.86}}

t = 0.07 seconds

An airbag is designed in such a way as to prevent the driver from hitting on the steering wheel or other hard substance that could damage the part of the body. The use of the seat belt is to keep the driver in shape and in a balanced position against the expansion that occurred by the airbag during the collision on the brick wall.

Thus, we can conclude that the airbag must be inflated at 0.07 seconds faster before the collision to effectively protect the driver.

Learn more about the kinematic equation here:

brainly.com/question/11298125?referrer=searchResults

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