Question

The heat of combustion of benzene, C6H6, is –41.74 kJ/g. Combustion of 4.50 g of benzene causes a temperature rise of 4.50°C in a certain bomb calorimeter. What is the heat capacity of this bomb calorimeter?

Answer 1

Answer:

Heat capacity this bomb calorimeter =  $41.74 KJ/^oC$

Explanation:

Given data we have in the question:

The heat of combustion for the benzene, $Q_{C_6H_6} = - 41.74 KJ/g$  (Here the negative sign depicts the release of heat and only magnitude is considered fro the heat capacity)

The mass of benzene, $M_{C_6H_6} = 4.50g$

The change in temperature due to the combustion, $\Delta T = 4.50^oC$

Now, the formula for the heat capacity is given as:

Heat capacity (C) = $\frac{Q_{C_6H_6}\times M_{C_6H_6}}{\Delta T }$

or

C =  $\frac{ 41.74 KJ/g\times 4.50g}{4.50^oC }$

or

C = $41.74 KJ/^oC$