A small 20-kg canoe is floating downriver at a speed of 2 m/s. 40 J is the canoe’s kinetic energy.
Answer: Option A
<u>Explanation:</u>
The given canoe has the mass and is being given to move at a speed. Therefore the kinetic energy of the canoe can be calculated using the following method,
Given that mass of the canoe = 20 kg and its speed =1 m/s
As we know that the Kinetic energy has the formula,
Therefore, substituting the value into the equation, we get,
= 40 J
Answer:
The weight lifter would not get past this sticking point.
Explanation:
Generally torque applied on the weight is mathematically represented as
T = F z
To obtain Elbow torque we substitute 4000 N for F (the force ) and 2cm for z the perpendicular distance
So Elbow Torque is
To obtain the torque required we substitute 300 N for F and 30cm
So the Required Torque is
Now since it mean that the weight lifter would not get past this sticking point
Answer:
The magnitude of the tangential velocity is
The magnitude of the resultant acceleration at that point is
Explanation:
From the question we are told that
The mass of the uniform disk is
The radius of the uniform disk is
The force applied on the disk is
Generally the angular speed i mathematically represented as
Where is the angular displacement given from the question as
is the angular acceleration which is mathematically represented as
The moment of inertial is mathematically represented as
Substituting values
Considering the equation for angular acceleration
Substituting values
Considering the equation for angular velocity
Substituting values
The tangential velocity of a given point on the rim is mathematically represented as
Substituting values
The radial acceleration at hat point is mathematically represented as
The tangential acceleration at that point is mathematically represented as
Substituting values
The magnitude of resultant acceleration at that point is
Substituting values