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Aleksandr [31]
3 years ago
13

Which statement best describes balancing equations and the law of conservation of mass?

Chemistry
2 answers:
max2010maxim [7]3 years ago
6 0

Answer:

The number of atoms is the same in the reactants and in the products, and the total mass is the same in the reactants and in

the products

Explanation:

For an equation to termed balance, the number of atoms of elements in the reactants must be equal to the number of atoms of the same element in the product.

The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but changes from one form to another. An unbalanced equation simply means that matter have been created or destroyed. This implies that balancing equation supports the laws of conservation of mass

hodyreva [135]3 years ago
6 0

Answer:

The answer is B

Explanation:

Just took the test

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K=+1

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Choose the thermochemical equation that illustrates ΔH°f for Li2SO4. Choose the thermochemical equation that illustrates ΔH°f fo
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Answer:

2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)  

Explanation:

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The only equation that meets those conditions is the last one.

A and B are wrong , because they show Li₂SO₄ as a reactant, not a product.

C is wrong because Li⁺ and SO₄²⁻ are not elements.

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A 720. cm^3 vessel contains a mixture of Ar and Xe. If the mass of the gas mixture is 2.966 g at 25.0°C and the pressure is 760.
sleet_krkn [62]

Explanation:

The given data is as follows.

      Pressure (P) = 760 torr = 1 atm

      Volume (V) = 720 cm^{3} = 0.720 L

     Temperature (T) = 25^{o}C = (25 + 273) K = 298 K

Using ideal gas equation, we will calculate the number of moles as follows.

                                PV = nRT

   Total atoms present (n) = \frac{PV}{RT}

                                          = 1 \times \frac{0.720 L}{0.0821 \times 298}

                                           = 0.0294 mol

Let us assume that there are x mol of Ar and y mol of Xe.

Hence, total number of moles will be as follows.

               x + y = 0.0294

Also,      40x + 131y = 2.966

             x = 0.0097 mol

              y = (0.0294 - 0.0097)

                = 0.0197 mol

Therefore, mole fraction will be calculated as follows.

Mol fraction of Xe = \frac{y}{(x+y)}

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Therefore, the mole fraction of Xe is 0.67.

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