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morpeh [17]
3 years ago
6

An object has rotational inertia I. The object,initially at rest, begins to rotate with a constant angularacceleration of magnit

ude alpha. What isthe magnitude of the angular momentum L ofthe object after time t?
Express your answer in terms ofI, alpha, andt.
L =
...............................................
Physics
1 answer:
Tresset [83]3 years ago
4 0

Answer:

L = I α t

Explanation:

given,                                          

rotational inertia = I              

initial velocity = ω₀                      

magnitude of acceleration = α      

angular momentum = L          

time = t                              

angular acceleration                                

\alpha = \dfrac{\omega-\omega_0}{t}

\alpha = \dfrac{\omega - 0}{t}

\alpha = \dfrac{\omega}{t}

ω = α t..............(1)

angular momentum                    

L = I ω                    

putting value from equation (1)

L = I α t                          

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Answer:

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Explanation:

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a) Therefore to convert -32°F to celsius, substitute it into the celsius

\begin{gathered} T_c=\frac{5}{9}(-32-32) \\  \\ T_c=\frac{5}{9}(-64) \\  \\ T_c=-35.6^0C \end{gathered}

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Answer:

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Explanation:

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Potential energy shifts:

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Now that's the energy necessary to lift a satellite of 100 kg to 300 km across the surface of the earth.

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This satellite is transmitted by it system at a height of 300 km and not in orbit, any other mechanism is required to bring the satellite into space.

6 0
3 years ago
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DanielleElmas [232]

Answer:

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Explanation:

Tangential velocity is given by the formula,

v= 2\pi r/ t

In the question given,

radius= 25meters

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pie= 3.14

number of laps= 1

The magnitude of tangential velocity equals;

\frac{1lap* 2 *3.14 *25m}{180secs}

<em>v </em>= 157<em>m</em>/180<em>secs</em>

Therefore, the magnitude of the tangential velocity

=0.872<em>m/secs</em>

5 0
2 years ago
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