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Contact [7]
3 years ago
15

tyhe mass of an object is 117 g adding 1200j of heat will raise the temperture of the object by 12 celsius what is the specifc h

eat of the object A 0.35 j/g *k B 6.8 j/g *k C 0.85 j/g*k D 42 j/g*k
Physics
1 answer:
Sati [7]3 years ago
8 0

Answer:

C 0.85 j/g*k

Explanation:

The specific heat capacity of a material is given by:

C_s = \frac{Q}{m \Delta T}

where

Q is the amount of heat supplied to the object

m is the mass of the object

\Delta T is the increase in temperature of the object

For the object in this problem, we have

m = 117 g is the mass

Q = 1200 J is the heat supplied

\Delta T=12^{\circ} is the increase in temperature

Substituting into the formula, we find the specific heat:

C_s = \frac{1200 J}{(117 g)(12^{\circ})}=0.85 J/gC

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An agriculturalist working with Australian pine trees wanted to investigate the relationship between the age and the height of t
SVETLANKA909090 [29]

Answer:

The correct answer is B.

Explanation:

Step 1:

The available regression equation is: Predict height= 0.29 + 0.48 (age).

Here, the predict height is dependent variable and the  age is in-dependent variable.

Intercept = 0.29

Slope      = 0.48

The given regression equation indicates the y on x model and the intercept coefficients of the regression equation is 0.29 and the slope is 0.48.

Step 2:

The height increases, an average, by 0.48 m per year.

Because co-efficient of slope variable indicate the positive sign and we increase 1 year in age then automatically height increased is 0.48 m.

<h3></h3><h3>The height increases, on average, by 0.48 meter each year.</h3>
6 0
4 years ago
Assuming typical speeds of 8.5 km/s and 5.5 km/s for P and S waves, respectively, how far away did the earthquake occur if a par
taurus [48]

Answer:

The earthquake occurred at a distance of 1122 km

Explanation:

Given;

speed of the P wave, v₁ = 8.5 km/s

speed of the S wave, v₂ =  5.5 km/s

The distance traveled by both waves is the same and it is given as;

Δx = v₁t₁ = v₂t₂

let the time taken by the wave with greater speed = t₁

then, the time taken by the wave with smaller speed, t₂ = t₁ + 1.2 min, since it is slower.

v₁t₁ = v₂t₂

v₁t₁ = v₂(t₁ + 1.2 min)

v₁t₁ = v₂(t₁ + 72 s)

v₁t₁ = v₂t₁ + 72v₂

v₁t₁ - v₂t₁ = 72v₂

t₁(v₁ - v₂) = 72v₂

t_1 = \frac{72v_2}{v_1-v_2}\\\\t_1 =   \frac{72*5.5}{8.5-5.5}\\\\t_1 = 132 \ s

The distance traveled is given by;

Δx = v₁t₁

Δx = (8.5)(132)

Δx = 1122 km

Therefore, the earthquake occurred at a distance of 1122 km

4 0
3 years ago
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MA_775_DIABLO [31]

Answer:

False?

Explanation:

Hope this helps you!

If this is wrong next time I will be better!

5 0
3 years ago
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Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direc
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Answer:

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Explanation:

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The relative speed will be calculated by using pythagorean theorem

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7 0
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What is a disadvantage of using nuclear power to produce electricity?
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Answer:

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Explanation:

3 0
3 years ago
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