tyhe mass of an object is 117 g adding 1200j of heat will raise the temperture of the object by 12 celsius what is the specifc h
1 answer:
Answer:
C 0.85 j/g*k
Explanation:
The specific heat capacity of a material is given by:
where
Q is the amount of heat supplied to the object
m is the mass of the object
is the increase in temperature of the object
For the object in this problem, we have
m = 117 g is the mass
Q = 1200 J is the heat supplied
is the increase in temperature
Substituting into the formula, we find the specific heat:
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Answer:
Q = 7272 Kilojoules.
Explanation:
<u>Given the following data;</u>
Mass = 2.0*101kg = 202kg
Initial temperature, T1 = 10°C
Final temperature, T2 = 90°C
We know that the specific heat capacity of iron = 450J/kg°C
*To find the quantity of heat*
Heat capacity is given by the formula;
Where;
- Q represents the heat capacity or quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity of water.
- dt represents the change in temperature.
dt = T2 - T1
dt = 90 - 10
dt = 80°C
Substituting the values into the equation, we have;
Q = 7272KJ or 7272000 Joules.
Answer:
The sponge must go deep
Explanation:
If F = 6360 N, then it is required to find how deep can an object with this force hitting on a sponge get.
We know that, F = mgh
m is mass
g is acceleration due to gravity
So, the sponge must go deep.
Answer:
The rotational inertia of the pendulum around its pivot point is .
Explanation:
The angular frequency of a physical pendulum is measured by the following expression:
Where:
- Angular frequency, measured in radians per second.
- Mass of the physical pendulum, measured in kilograms.
- Gravitational constant, measured in meters per square second.
- Straight line distance between the center of mass and the pivot point of the pendulum, measured in meters.
- Moment of inertia with respect to pivot point, measured in
.
In addition, frequency and angular frequency are both related by the following formula:
Where:
- Frequency, measured in hertz.
If , then angular frequency of the physical pendulum is:
From the formula for the physical pendulum's angular frequency, the moment of inertia is therefore cleared:
Given that ,
,
and
, the moment of inertia associated with the physical pendulum is:
The rotational inertia of the pendulum around its pivot point is .