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ki77a [65]
3 years ago
6

To teach you how to find the parameters characterizing an object in a circular orbit around a much heavier body like the earth.

The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were observed by Tycho Brahe and analyzed by Johannes Kepler. A good starting point for understanding this (as well as the speed of the space shuttle and the height of geostationary satellites) is the simplest orbit--a circular one. This problem concerns the properties of circular orbits for a satellite orbiting a planet of mass M. For all parts of this problem, where appropriate, use G for the universal gravitational constant. Part A) Find the orbital speed v for a satellite in a circular orbit of radius R. (Express the orbital speed in terms of G, M, and R),Part B) Find the kinetric energy K of a satellite with mass m in a circular orbit with radius R. (Express your answer in terms of m, M, G, and R).Part D) Find the orbital period T. (Express your answer in terms of G, M, R, and pi).
Physics
1 answer:
laila [671]3 years ago
5 0

Answer:

a) v = √(GM/R), b)   K = ½ G m M /R and d)  T = 2π R√(R/GM)

Explanation:

This problem should use the law of universal gravitation

    F = G m M / r²

a) For this part we use Newton's second law where acceleration is centripetal

    F = m a

Centripetal acceleration is

    a = v² / r

    F = m v² / r

    G m M / r² = m v² / r

    G M / r = v²

We use the distance (R) measured from the center of the planet

    v = √(GM / R)

b) the expression for kinetic energy is

    K = ½ m v²

    K = ½ m G M / R

    K = ½ G m M / R

d) as the velocity module is constant, we can use the equation and uniform motion

    v = d / T

    T = d / v

The distance is the length of the circle

   d = 2π R

   T = 2π R / √(GM / R)

   T = 2π R √ (R / GM)

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The best answer to this question is D. a god scientific question should be based on observations instead of just imagination.

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3 years ago
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Find the cost of excavating a space 84 ft long, 42 ft wide, and 9 ft deep at a cost of $39/yd3. (simplify your answer completely
m_a_m_a [10]

The cost of excavating a space of 84 ft long, 42 ft wide, and 9 ft deep is $45864

Information about the problem:

  • Space long= 84 ft
  • Space wide= 42 ft
  • Space deep= 9 ft
  • Cost by yard3 = $39/yd3
  • Total cost= ?

To solve this problem, we have to state the equation using the information of the problem:

Calculating the volume of the total space:

space volume = space long * space wide * space deep

space volume = 84 ft * 42 ft * 9 ft

space volume = 31752 ft3

By converting the volume from ft3 to yd3, we have:

31752 ft3 * (0,037037 yd3 / 1 ft3) = 1176 yd3

Calculating the cost of excavating the volume space:

Total cost = space volume * cost by yard3

Total cost = 1176 yd3 * $39/yd3

Total cost = $45864

<h3>What is volume?</h3>

It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.

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4 0
2 years ago
Which statement best explains why atoms form chemical bonds with other atoms?
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Because atoms is something that pops or has bubbles in it
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3 years ago
the presence of which magnetic feature best explains why a magnet can act a distance on other magnets or on objects containing c
katen-ka-za [31]

Magnetic fields

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The presence of magnetic fields  best explains why a magnet can act a distance on other magnets or on objects containing certain metals.

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8 0
3 years ago
(a) What is the entropy change of a 14.6 g ice cube that melts completely in a bucket of water whose temperature is just above t
Alex73 [517]

Answer:

a) 17.81 J/K

b) 33.325 J/K

Explanation:

The expression to use here is the following:

ΔS = Q/T

Where:

Q: heat released or absorbed

T: Temperature in K

Now, in order to do this, we need to gather the data. We know that the temperature in part a) is above the freezing temperature of water, which is 0 ° C or 273 K. and the mass of the ice cube is 14.6 g.

a) Using the water heat of fusion (Cause it's melting), we can calculated the heat released using the following expression:

Q = m * Lf

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Solving for Q first we have:

Q = (14.6 / 1000) * 333,000

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Now, the entropy change is:

ΔS = 4,861.8 / 273

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b) In this part, we follow the same procedure than in part a) but using the water heat of boiling (Lv = 2,256,000 J/kg), the temperature of boiling which is 100 °C (or 373 K) and the mass of 5.51 g (0.00551 kg)

Calculating the heat:

Q = 0.00551 * 2,256,000 = 12,430.56 J

Now the entropy change:

ΔS = 12,430.56 / 373

ΔS = 33.325 J/K

8 0
3 years ago
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