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Bas_tet [7]
3 years ago
9

If the spring constant is doubled, what value does the period have for a mass on a spring?

Physics
2 answers:
soldi70 [24.7K]3 years ago
4 0

if spring constant is doubled, the mass on spring will be doubled as well. according to this formula, F=ke

k stands for spring constant and e stands for the length extended

alexandr402 [8]3 years ago
3 0
The period T = 2 pi square root ( k / m )
If the spring constant k is doubled then T increases by a factor of square root 2 so it becomes (square root 2) * T
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a 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
Lesechka [4]

The final velocity is 3.47 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v

where:

m_1 = 91.5 kg is the mass of the first player

u_1 = 3.73 m/s is the initial velocity of the first player (we take east as positive direction)

m_2 = 63.5 kg is the mass of the second player

u_2 = 3.09 m/s is the initial velocity of the second player

v is their final combined velocity after the collision

Re-arranging the equation and substituting the values, we find:

v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(3.73)+(63.5)(3.09)}{91.5+63.5}=3.47 m/s

So, their velocity afterwards is 3.47 m/s east.

Learn more about momentum:

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6 0
3 years ago
Mike enters a revolving door that is not moving. explain where and how mike should push to produce a torque with the least amoun
Bingel [31]

Mike enters a revolving door that is not moving. Mike should push at the edge of the door where it is largest distance from the pivot point in order to produce a torque with the least amount of force. Torque is equal to t = force x distance.

7 0
4 years ago
Read 2 more answers
There is a potential difference of 1.1 V between the ends of a 10 cm long graphite rod that has a cross-sectional area of 0.90 m
Serga [27]

Explanation:

It is given that,

Potential difference between the ends of a rod, V = 1.1 V

Length of the rod, l = 10 cm = 0.1 m

Area of cross section of the rod, A=0.9\ mm^2=9\times 10^{-7}\ m^2

The resistivity of graphite, \rho=7.5\times 10^{-6}\ \Omega-m

(a) Let R is the resistance of the rod. It is given by :

R=\rho \dfrac{l}{A}

R=7.5\times 10^{-6}\times \dfrac{0.1}{9\times 10^{-7}}

R=0.833\ \Omega

So, the resistance of the rod is 0.833 ohms.

(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :

I=\dfrac{V}{R}

I=\dfrac{1.1\ V}{0.833\ \Omega}

I = 1.32 A

(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :

E=\dfrac{V}{l}

E=\dfrac{1.1\ V}{0.1\ m}

E = 11 V/m

Hence, this is the required solution.

8 0
3 years ago
A bicycle has a momentum of 36 kg* m/s and a very!I city of 4 m/s.What is the mass of the bicycle?
Strike441 [17]

p = 36 kgm/s

v = 4m/s

we know that,

p = mv

so,

m =  \frac{p}{v}

m  =  \frac{36}{4}

m = 9kg

8 0
3 years ago
I would like to know why this is the correct answer
Helen [10]

The acceleration of the object if the net force is decreased = 0.13 m/s²

<h3>Further explanation</h3>

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

\tt \sum F=m.a

The mass used in state 1 and 2 remains the same, at 1.5 kg

  • state 1

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2

  • state 2

ΣF=0.2 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2

8 0
3 years ago
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