Answer:

Explanation:
- First rearrange the whole equation by keeping t in one side and rest parameters in another side of equation
- Then plug-in all the given values for each parameters and get the solution

or, 
Now plug-in all given values:

So, 
<span>Rules for the Principal Energy Level. A principal energy level may contain up to 2n2 electrons, with n being the number of each level. The set of three p orbitals can hold up to 6 electrons. Thus, the second principal energy level can hold up to 8 electrons, 2 in the s orbital and 6 in the p orbital.</span>
The statement above is TRUE.
Cornstarch is a carbohydrate which is made up of hydrogen, carbon and oxygen. Cornstarch is a refined carbohydrate, which is made up of pure starch; no nutrient is added to it. Corn starch is usually obtained from the endosperm of corn.
Answer:
Wavelength, 
Explanation:
We have,
Velocity of the object, 
Mass of the object, 
It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

h is Planck's constant

So, the wavelength of the object is
.
The answer to the question is radium (Ra)