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musickatia [10]
3 years ago
15

An atom with 9 protons and 10 neutrons in its nucleus and 9 electrons in movement around the nucleus would be an atom of which e

lement?
A: Beryllium
B: Neon
C: Fluorine
D: Potassium
Chemistry
2 answers:
inna [77]3 years ago
6 0

<u>Answer:</u> The element is Fluorine.

<u>Explanation:</u>

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

Atomic mass is defined as the sum of number of protons and neutrons that are present in an atom.

Atomic mass = Number of protons + Number of neutrons

We are given:

Number of protons = 9 = Atomic number

Number of electrons = 9

Number of neutrons = 10

Mass number = 9 + 10 = 19

The element having atomic number equal to 9 and mass number equal to 19 is fluorine.

Hence, the element is Fluorine.

Valentin [98]3 years ago
5 0
The correct answer is C.  We know this is true since the number of protons an atom has is its atomic number.  Since this atom  has 9 protons, look for the element on the periodic table that has an atomic number of 9.  The element that has an atomic number of 9 is flouring.

I hope this helps.
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3 years ago
In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine t
exis [7]

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89.3 %

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1)                                  CH4        + 2O2 -----> CO2 + 2H2O

from reaction             1 mol          2 mol

given                       0.5313 mol   (0.4969 mol)

1 mol CH4              --- 2 mol O2

0.5313 mol  CH4  --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2)                               CH4        + 2O2 -----> CO2 + 2H2O

from reaction                             2 mol        1 mol

given                                      0.4969 mol   x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

3)

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %

7 0
3 years ago
What is described in the following equation?
Alexus [3.1K]

Answer:

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