Moles of K = 32.4/39 = 0.83 mole. According to stoichiometry, 2 moles of K produces 1mole of H2. Therefore, 0.83 mole of K produces = 0.83/2 = 0.415 moles of H2. Therefore number molecules of H2 = moles of H2 x 6.02 x 10^23 = 2.4983 x 10^23 molecules. Hope this helps!
Answer:
2000 mL
Explanation:
Given data:
Number of moles KMnO₄ = 6 mol
Molarity of solution = 3M
Volume of solution in mL = ?
Solution:
Formula:
Molarity = number of moles of solute / volume of solution in L
3 M = 6 mol / volume of solution in L
volume of solution in L = 6 mol/ 3 M
volume of solution in L = 2 L
Now we convert the L into mL:
1 L = 1000 mL
2 L × 1000 mL / 1 L
2000 mL
<h3>
Answer:</h3>
6
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 2AgNO₃ (aq) + Cu (s) → Cu(NO₃)₂ (aq) + 2Ag (s)
<u>Step 2: Identify</u>
Reactants: 2AgNO₃ (aq) + Cu (s)
# of O atoms: 2(O₃) = 6 O
