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worty [1.4K]
3 years ago
15

Haylie wanted to see if the type of paper changed how far a paper airplane flew. She made two paper airplanes, one with construc

tion paper and one with lined notebook paper. What scientific tool would she need to conduct her experiment? (btw this is science, I just cant find science)
Physics
2 answers:
Irina-Kira [14]3 years ago
6 0

Answer:

Measuring tape

Explanation:

Since we are interested in finding the distance flown by the plane, we would use an instrument measuring length. Since distance flown by the plane is quite significant, a measuring tape is used

exis [7]3 years ago
5 0

Answer: Measuring tape

  Hope this helped please put as brainlist. also I gave you a thanks HAHAjoke

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b. active solar heating systems

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A solar collector is a device that collects and/or concentrates solar radiation from the Sun. These devices are primarily used for active solar heating and allow for the heating of water for personal use.

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What information do rocks provide to<br> geologists?
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Calculate the net force if the forces are parallel 4N 4N
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Answer:

The net force is zero Newtons (0 N).

Explanation:

If the forces on one side is 4N and the forces on another side are 4N, the forces cancel out and you have a net force of zero. This means the object is at rest or is moving at a constant rate based on the question.

Hope this helps!

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3 years ago
Read 2 more answers
The approximate rotation period of the Moon is: A. 1 day B. 1 week C. I month D. Infinite, since the Moon does not rotate, but k
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Answer:

C. 1 month

Explanation:

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7 0
4 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
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