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Sholpan [36]
3 years ago
8

Determine the molecular weight for Mg(NO3)2

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
The molecular weight is the same as molecular mass. You find this by using the periodic table 
The molar mass of Mg(NO3)2 is 148.3
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You make a solution by putting 45.6g of iron lll carbonate into 167ml of water. What is it's molarity?
ludmilkaskok [199]
1. The molar mass of Fe2(CO3)3 is 291.72 g/mol. This means that 45.6 g is equivalent to 0.156 mol. Dividing by the 0.167 L of water gives a solution of 0.936 M.
2. Multiplying (0.672 M)(0.025 L) = 0.0168 mol. The molar mass of Ni(OH)2 is 92.71 g/mol, so multiplying by 0.0168 mol = 1.56 grams. Therefore you would need to dissolved 1.56 g of Ni(OH)2 into 25 mL of water.
3. Fe2(CO3)3 + Ni(OH)2 --> Fe(OH)3 + NiCO3Balancing: Fe2(CO3)3 + 3Ni(OH)2 --> 2Fe(OH)3 + 3NiCO3The reaction quotient is:[Fe(OH)3]^2 * [NiCO3]^3 / [Fe2(CO3)3][Ni(OH)2]^3= (0.05)^2 * (1.45)^3 / (0.936)(0.672)^3= 0.0268Since this is < 1, it implies that the reactants are favored at equilibrium.
4 0
3 years ago
NEED HELP QUICKLY!!! How many moles are in each of the following?
oksano4ka [1.4K]

Answer: a. 0.26mol

b. 0.000479mol

c. 1.12mol

Explanation: Please see attachment for explanation

6 0
3 years ago
1) If the pressure on 2.6 liters of a gas at 860 Torr is increased to 1000 Torr,
LenKa [72]

2.24 liters is the volume of the gas if pressure is increased to 1000 Torr.

Explanation:

Data given:

Initial volume of the gas V1 = 2.6 liters

Initial pressure of the gas P1 = 860 Torr 1.13 atm

final pressure on the gas P2 = 1000 Torr 1.315 atm

final volume of the gas after pressure change V2 =?

From the data given above, the law used is :

Boyles Law equation:

P1V1 = P2V2

V2 = P1V1/P2

   = 1.13 X 2.6/ 1.31

  = 2.24 Liters

If the pressure is increased to 1000 Torr or 1.315 atm the volume changes to 2.24 liters. Initially the volume was 2.6 litres and the pressure was 860 torr.

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Answer: An island.

"A piece of land surrounded by water"

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4 years ago
a transistor has beta=180 calculate the approximate collector and base currents if the emitter current is 10ma
zysi [14]

Answer:

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Explanation:

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