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natima [27]
2 years ago
7

How many orbitals are in Phosphorus

Chemistry
2 answers:
Viefleur [7K]2 years ago
8 0

Answer:

3

three half-filled orbitals each capable of forming a single covalent Bond and an additional lone - pair of electrons

Nastasia [14]2 years ago
3 0
5 orbits are in phosphorus
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If a sample contains 100.0 g of lead atoms (Pb), how many atoms are present in the sample?
Igoryamba

Answer:

The answer to your question is the letter C. 2.906 x 10²³ atoms

Explanation:

Data

mass of Lead = 100 g

The Number of atoms = ?

Process

1.- Look for the atomic number of Lead in the periodic table

Atomic number = 207.2 g

2.- Use proportions and the Avogadro's number to calculate the number of atoms.

                      207.2 g ------------------ 6.023 x 10²³ atoms

                       100 g    -----------------   x

                       x = (100 x 6.023 x 10²³) / 207.2

                       x = 6.025 x 10²⁵ / 207.2

                      x = 2.906 x 10²³ atoms

7 0
3 years ago
Read 2 more answers
With the given chemical compounds, what is the balanced chemical equation when lit with fire?
Alchen [17]

Answer:

Russia es el mejor pais? Vladimir Putin, es el mejor presidente del mundo

8 0
3 years ago
The rate constant for a certain reaction is k = 4.70×10−3 s−1 . If the initial reactant concentration was 0.700 M, what will the
Lynna [10]

Answer:

Therefore the concentration of the reactant after 4.00 minutes will be 0.686M.

Explanation:

The unit of k is s⁻¹.

The order of the reaction = first order.

First order reaction: A first order reaction is  a reaction in which the rate of reaction depends only the value of the concentration of the reactant.

-\frac{d[A]}{dt} =kt

[A] = the concentration of the reactant at time t

k= rate constant

t= time

Here k= 4.70×10⁻³ s⁻¹

t= 4.00

[A₀] = initial concentration of reactant = 0.700 M

-\frac{d[A]}{dt} =kt

\Rightarrow -\frac{d[A]}{[A]}=kdt

Integrating both sides

\Rightarrow\int -\frac{d[A]}{[A]}=\int kdt

⇒ -ln[A] = kt +c

When t=0 , [A] =[A₀]

-ln[A₀]  = k.0 + c

⇒c= -ln[A₀]  

Therefore

-ln[A] = kt - ln[A₀]

Putting the value of k, [A₀] and t

- ln[A] =4.70×10⁻³×4 -ln (0.70)

⇒-ln[A]=  0.375

⇒[A] = 0.686

Therefore the concentration of the reactant after 4.00 minutes will be 0.686M.

5 0
3 years ago
If 75 grams of oxygen react, how many grams of aluminum are required?
german

Answer:

84.24 g

Explanation:

Given data:

Mass of oxygen = 75 g

Mass of Al required to react = ?

Solution:

Chemical equation:

4Al + 3O₂     →   2Al₂O₃

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 75 g/ 32 g/mol

Number of moles = 2.34 mol

Now we will compare the moles of oxygen with Al.

                          O₂         :          Al

                           3          :             4

                        2.34        :         4/3×2.34 = 3.12 mol

Mass of Al required:

Mass = number of moles × molar mass

Mass = 3.12 mol × 27 g/mol

Mass = 84.24 g

5 0
3 years ago
Formation of water: 2H2 + 1 O2 --> 2H2O
noname [10]

Answer:

2.2 moles H2O

Explanation:

35g O_2 \mbox{ \cdot }\frac{1mol}{32g/mol} \mbox{ \cdot }\frac{2mol H_2O}{1mol O_2}= 2.1875, which rounds to about 2.2

7 0
2 years ago
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