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natima [27]
2 years ago
7

How many orbitals are in Phosphorus

Chemistry
2 answers:
Viefleur [7K]2 years ago
8 0

Answer:

3

three half-filled orbitals each capable of forming a single covalent Bond and an additional lone - pair of electrons

Nastasia [14]2 years ago
3 0
5 orbits are in phosphorus
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How many moles are equal to 89.23g of calcium oxide, CaO?
Katen [24]

1.59moles

Explanation:

Mass  of CaO = 89.23g

Unknown

Number of moles = ?

Solution:

The mole is a unit of measurement in chemistry used to delineate the number of particles an atom contains.

A mole of a substance contains the avogadro's number of particles.

Number of moles = \frac{mass}{molar mass}

Molar mass of CaO = 40 + 16 = 56g/mol

  Number of moles = \frac{89.23}{56} = 1.59moles

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

8 0
3 years ago
Calculate the pH of the resulting solution if 26.0 mL of 0.260 M HCl(aq) is added to:
enyata [817]
So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
7 0
3 years ago
NaHCO 3 and NaHSO 4 are acid salts. however aqueous solution of NaHCO 3 is basic while aqueous solution of NaHSO 4 is acidic. gi
posledela

Answer:c

Explanation:

3 0
3 years ago
When the concentration of A in the reaction A ..... B was changed from 1.20 M to 0.60 M, the half-life increased from 2.0 min to
Reika [66]

Answer:

2

0.4167\ \text{M}^{-1}\text{min}^{-1}

Explanation:

Half-life

{t_{1/2}}A=2\ \text{min}

{t_{1/2}}B=4\ \text{min}

Concentration

{[A]_0}_A=1.2\ \text{M}

{[A]_0}_B=0.6\ \text{M}

We have the relation

t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}

So

\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}

Comparing the exponents we get

1=n-1\\\Rightarrow n=2

The order of the reaction is 2.

t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}

The rate constant is 0.4167\ \text{M}^{-1}\text{min}^{-1}

3 0
2 years ago
Why is it better to measure the percent change in mass<br> ratherthan just using the change in mass?
never [62]

Answer: The result is presented in proportion which gives a clearer understanding and accurate result.

Explanation: Percentage change in mass is the proportion of the initial mass of a substance changed after sometime. The results is presented as a percentage making it more accurate and can help to give future reference to weight calculations.

Change is Mass is the mass of a substance left after sometime mostly given in grams. It is not as accurate as percentage change in mass. It is generally better to show results in percentage change in mass as it gives a better understanding of what mass of a substance was lost after a given period or after application of energy like Heat or increased temperature.

6 0
3 years ago
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