Reaction involved in present electrochemical cell,
At Anode: Zn → Zn^2+ + 2e^2-
At cathode: Zn^2+ + 2e^2- → Zn
Net Reaction: Zn + Zn^2+ ('x' m) → Zn^2+(0.1 m) + Zn
Number of electrons involved in present electrochemical cell = n = 2
According to Nernst equation for electrochemical cell,
Ecell = -2.303
![\frac{RT}{nT} log \frac{[Zn^2+]R}{[Zn^2+]L}](https://tex.z-dn.net/?f=%20%5Cfrac%7BRT%7D%7BnT%7D%20log%20%20%5Cfrac%7B%5BZn%5E2%2B%5DR%7D%7B%5BZn%5E2%2B%5DL%7D%20%20)
= 0.014
Given: T =
, F = 96500 C, R = gas constant = 8.314J/K.mol, [Zn^2+]R = 0.1 m , Ecell = 0.014 v
∴ 0.014 = - 2.303
∴ log
=
= -2.1117
∴ log x = log(0.1) + 2.1117
∴x = 13.09 m
The balanced equation for the above reaction is as follows;
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
stoichiometry of octane to CO₂ is 2:16
number of C₈H₁₈ moles reacted - 191.6 g / 114 g/mol = 1.68 mol
when 2 mol of octane reacts it forms 16 mol of CO₂
therefore when 1.68 mol of octane reacts - it forms 16/2 x 1.68 = 13.45 mol of CO₂
number of CO₂ moles formed - 13.45 mol
therefore mass of CO₂ formed - 13.45 mol x 44 g/mol = 591.8 g
mass of CO₂ formed is 591.8 g
<h2>A : Hamstrings</h2><h2 /><h2>B : Ligament</h2><h2 /><h2>C : Meniscus</h2><h2 /><h2>D : * think this is Ligament too! hope im right</h2><h2 /><h2>E : Femur (Thigh Bone)</h2>
Answer:
4,2,1,3
Explanation:
4. A small ribosomal subunit binds to a molecule of mRNA5. the anticodon of an incoming aminoacyl tRNA base-pairs with the complementary mRNA codon in the A site.
2. The large ribosomal subunit attaches with the initiator tRNA with the amino acid methionine (Met) located in the P site.
1. The ribosome translocates the tRNA in the A site to the P site and the empty tRNA in the P site is moved to the E site where it is released.
3. A release factor, a protein shaped like an aminoacyl tRNA, promotes hydrolysis and releases the polypeptide.
