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Serjik [45]
3 years ago
14

Endothermic or exothermic?

Chemistry
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

Endothermic

Exothermic

Endothermic

Exothermic

Exothermic

Exothermic

Explanation:

Endothermic is when a reaction absorbs heat.

Exothermic is when a reaction releases heat.

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What is the symbol for temperature?<br><br> m<br><br> q<br><br> T<br><br> J
Tcecarenko [31]

Answer:

T

Explanation:

m is mass

q is heat

J is energy

6 0
1 year ago
How many grams of Sodium will have the same number of atoms as 6 grams of Magnesium?
Ksivusya [100]

Answer:

92gm

Explanation:

Atomic mass of Mg=24g=1 mole of Mg

∴  24g =1 mole of Mg contain 6.022×10^23 atom 

∴  6gm contains 246.022×1023×6

                            =4×6.022×10^23 atoms

Now according to question, there are 6.022×1023 atoms of Na 

23gm of Na contains 6.022×10^23 atoms

∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm

3 0
3 years ago
Which is not a compound? a)Gold b)water c)sugar D)silicon dioxide
sweet [91]
Gold is an element. Water is made from hydrogen and oxygen, and silicon dioxide is an oxide of silicon, consisting of <span> two oxygen atoms and one silicon</span>
8 0
2 years ago
Which is associated with a fission reaction? *
podryga [215]

Answer: Radioactive waste

Explanation:

The nuclear fission reaction consists of heavy atomic particles or heavy nucleus, like plutonium and uranium and in radioactive heavy metals. In the fission reaction the nucleus get split into equal masses of particles. This process is associated with release of large amount of energy. The fission of radioactive waste can cause deadly mutations in living beings.      

6 0
3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
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