Explanation:
The attraction between solute particles affect its ability to dissolve in the solution because more is the attraction between particles less will be the chances that solute particles will combine to the solvent particles.
As a result, there will be decrease in solubility with increase in force of attraction between solute particles.
Whereas when there is less force of attraction between solute particles then more easily solute particles will combine with the solvent particles.
Hence, with decrease in force of attraction between solute particles, the rate of dissolution will increase.
The bond angle obtained based on the geometry of the molecule alone is known as the predicted bond angle.
When a compound is formed, the less electronegative atom in the compound is called the central atom in the molecule. The angle formed by the nuclei of two surrounding atoms with the nucleus of the central atom in a structure is called a bond angle.
The bond angle is usually based on the geometry of the molecule. The expected geometry can be deviated for certain reasons such as the presence of lone pairs on the central atom in the molecule. The bond angle obtained based on the geometry of the molecule alone is known as the predicted bond angle.
Learn more about bond angle: brainly.com/question/6179102
Answer:
The answer to your question is:
Explanation:
Compound Cation Anion Number of electrons
LiCl Li⁺¹ Cl⁻¹ one
NaF Na⁺¹ F⁻¹ one
CaO Ca⁺² O⁻² two
BaS Ba⁺² S⁻² two
NaBr Na⁺¹ Br⁻¹ one
Answer:
13.85 kJ/°C
-14.89 kJ/g
Explanation:
<em>At constant volume, the heat of combustion of a particular compound, compound A, is − 3039.0 kJ/mol. When 1.697 g of compound A (molar mass = 101.67 g/mol) is burned in a bomb calorimeter, the temperature of the calorimeter (including its contents) rose by 3.661 °C. What is the heat capacity (calorimeter constant) of the calorimeter? </em>
<em />
The heat of combustion of A is − 3039.0 kJ/mol and its molar mass is 101.67 g/mol. The heat released by the combustion of 1.697g of A is:
According to the law of conservation of energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.
Qcomb + Qcal = 0
Qcal = -Qcomb = -(-50.72 kJ) = 50.72 kJ
The heat capacity (C) of the calorimeter can be calculated using the following expression.
Qcal = C . ΔT
where,
ΔT is the change in the temperature
Qcal = C . ΔT
50.72 kJ = C . 3.661 °C
C = 13.85 kJ/°C
<em>Suppose a 3.767 g sample of a second compound, compound B, is combusted in the same calorimeter, and the temperature rises from 23.23°C to 27.28 ∘ C. What is the heat of combustion per gram of compound B?</em>
Qcomb = -Qcal = -C . ΔT = - (13.85 kJ/°C) . (27.28°C - 23.23°C) = -56.09 kJ
The heat of combustion per gram of B is:
Number of moles = volume / (molar volume)
Molar volume at stp = 22.4 dm^3
Volume = no of moles × molar volume
= 0.987 × 22.4
= 22.1088 dm^3
= 22108.8 cm^3
Hope it helped!
