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3 years ago

Which statement describe. good hypothesis ? Check all that apply

1 answer:

7 0

A good hypothesis describes your ideas and how you think the experiment will conclude. Additionally, hypotheses have scientific information included.

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Briefly describe the difference between the CPC, COC, and CIC certifications. Can you work in a hospital or outpatient facility

madreJ [45]

Answer : the difference between the CPC, COC, and CIC Certified Professional Coder , Certified Outpatient Coder ,Certified Inpatient Coder

Explanation :

CPC - Certified Professional Coder is the gold standerd for medical coding in a physician.

COC - Certified Outpatient Coder is the only standalone outpatient coding credential in the healthcare .

CIC - Certified Inpatient Coder is the only standalone inpatient coding credential in the healthcare .

Yes, we can work in hospital and outpatient facility in COC.

If we have a professional certifications in coding then we can make a best physician.

Yes, credential is important because we can recognize that the doctor works in which field.

4 0

3 years ago

(Figure 1) shows the voltage across a 0.10 μF capacitor. Select the correct graph showing the displacement current through the c

Lilit [14]

Answer:

The answer is the third photo

Explanation:

3 0

2 years ago

Friction marks are made by tools that indent a surface. True or false

k0ka [10]

This statement is True.

6 0

2 years ago

Read 2 more answers

An automobile of mass 2500 kg moving at 49.4 m/s is braked suddenly with a constant braking force of 8,868 N. How far does the c

BaLLatris [955]

Answer:

344.68 m

Explanation:

The computation of the far does the car travel before stopping is

Data provided in the question

Force = F = 8,868 N

mass = m = 2,500 kg

So,

accleration = a is

$= \frac{-F}{m}\\\\\= \frac{8868}{2500}$

a = -3.54 m/s^2

The initial speed = u = 49.4 m / s

final speed = v = 0

Based on the above information

Now applying the following formula

v^ 2- u^ 2= 2aS

Therefore

$S = \frac{v^ 2- u^ 2}{2a}\\\\\ = \frac{0- 49.4^ 2}{2\times -3.54}$

= 344.68 m

4 0

3 years ago

If you triple the speed from 20km/h to 60km/h, by what factor does the KE increase?

sertanlavr [38]

Answer:

The kinetic energy increases by a factor of 9

Explanation:

Kinetic Energy

It's the energy related to the speed of an object and is calculated by the formula

$\displaystyle K=\frac{mv^2}{2}$

Let's suppose the initial speed of the mass is $v_o$ , then the kinetic energy is

$\displaystyle K_o=\frac{mv_o^2}{2}$

Now the speed will triple, i.e. $v_1=3v_o$ . The new kinetic energy is

$\displaystyle K_1=\frac{mv_1^2}{2}$

$\displaystyle K_1=\frac{m(3v_o)^2}{2}$

$\displaystyle K_1=9\frac{mv_o^2}{2}$

Thus

$K_1=9K_o$

The kinetic energy increases by a factor of 9

Let's check with numbers: $v_o=20,\ v_1=60$

$\displaystyle K_o=\frac{m20^2}{2}=200m$

$\displaystyle K_1=\frac{m60^2}{2}=1800m$

The relation is

$\displaystyle \frac{K_1}{K_o}=9$

The new kinetic energy is nine times the initial kinetic energy.

5 0

3 years ago