Answer:
6 m/s
Explanation:
mass of moving car m1=5000 kg
initial velocity of moving car vi1=?
mass of car at rest = m2=10000 kg
initial velocity of car at rest = vi2=0
final velcoities of both cars after collision = vf1=vf2= 2m/s
using conservation of momentum rule
m1vi1+m2vi2=m1vf1+m2vf2
putting values
==> 5000 × vi1 + 1000 × 0 = 5000 × 2 + 10000 × 2
==> 5000 ×vi1 = 2 × 15000
==> vi1 = 2 × 15000 ÷ 5000
==> vi1= 2×3=6 m/s
work done = force * distance
work = 62 * 2 = 124 j
270/70^2 = x/80^2
Cross multiply
270 (6400) = 4900x
x = 270(6400)/4900
352 and 32/49 feet
Hope this helps
I think it’s D sorry If I’m wrong
