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Sholpan [36]
3 years ago
7

A block with an initial kinetic energy of 4.0 J comes to rest after sliding 1.0 m. How far would the block slide if it had 8.0 J

of initial kinetic energy?
Physics
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

2.0 m

Explanation:

Kinetic Energy: This is the energy of a body due to motion.

According to the law of conservation of energy,

Kinetic Energy = potential Energy = mgs

Where m = mass (kg) , g = acceleration due to gravity (m/s²) , s = distance or height (m).

Kinetic energy = 4.0 J , s = 1.0 m , g= 9.8m/s² , m=?

∴ m = kinetic Energy/(gs)

 m = 4/(1 ×9.8) = 0.4081 Kg.

When the initial kinetic energy  8.0 J

∴ Distance (s) = 8.0/(0.4081 × 9.8)

    Distance (s) = 2.00031

     Distance (s) ≈ 2.0 m

∴  the block would slide 2.0 m

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The membrane of a living cell can be approximated by a parallel-plate capacitor with plates of area 4.50×10−9 m2 , a plate separ
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Explanation:

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brainly.com/question/10427437

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Answer:

compression of spring is x = 0.12 m

Assumed k = 160,000 N/m ........ Truck's suspension system

Explanation:

Given:

- The mass of average person m_p = 69 kg

- Total number of persons n_p = 27

- The mass of each goat m_g = 15 kg

- The total number of goats n_g = 3

- The mass of each chicken m_c = 3 kg

- The total number of goats n_c = 5

- The total mass of bananas m_b = 25 kg

Find:

How much are the springs compressed?

Solution:

- Using equilibrium equation on the taptap in vertical direction:

                                 F_net = F_spring - F_weight = 0

- Compute the force due to all the weights on the taptap:

                                F_weight = (n_p*m_p + n_g*m_g + n_c*m_c + m_b)*9.81

                                F_weight = (69*27 + 3*15 + 5*3 + 25)*9.81  

                                F_weight = 19109.88 N

- The restoring force of a spring is given by:

                                F_spring = k*x

Where, k is the spring stiffness and x is the displacement:

                                 F_weight = F_spring

                                 19109.88 = k*x

                                 x = 19109.88 / k

We need to assume the spring stiffness we will take k = 160,0000 N/m (trucks suspension systems). The value of the stiffness must be high enough to sustain a load of 1.911 tonnes.

                                 x = 19109.88 / 160,000

                                 x = 0.1194 m ≈ 0.12 m = 12 cm

- A compression of 12 cm seems reasonable for a taptap to carry 1.911 tonnes of load. Hence, the assumption of spring stiffness was reasonable. Hence, the compression of spring is x = 0.12 m.

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