A transverse wave is moving toward the right in a uniform medium. Point X represents a particle of the uniform medium. Which dia
gram represents the direction of the motion of particle X at the instant shown?
2 answers:
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Answer:
Explanation:
From the position coordinates given , it appears that the ball moves simultaneously along x and y direction.
Displacement along x direction in one second = 4.4 - 1.8 = 2.6 m
So velocity along x direction V_x =
Similarly velocity along y direction V_y(1) =
In the next phase velocity changes both in x and y direction.
velocity in x - direction V_x(2) = [tex]\frac{2}{s}[/tex
Velocity in Y- direction V_y(2) = [tex]\frac{3.1}{s}[/tex
Acceleration in x direction = change of velocity in x direction
= ( 2 - 2.6 ) = -.6 m s⁻²
Acceleration in y direction = ( 3.1 - 2.6 ) = 0.5 m s⁻²
Total acceleration =\sqrt{( -.6 )² + ( .5 )²}
= .78 ms⁻²
Answer:
a = 603.59 m/s^2
Explanation:
from the data given . the rate of change in magnetic field is as follow
from the faraday's law of induction , the expression for the induced emf in region of radius r as follow
electric field at point P_1 as follow
from newton 2nd law of motion, the acceleration of proton is
F = ma
qE = ma
a = 603.59 m/s^2