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exis [7]
2 years ago
6

A transverse wave is moving toward the right in a uniform medium. Point X represents a particle of the uniform medium. Which dia

gram represents the direction of the motion of particle X at the instant shown?

Physics
2 answers:
trapecia [35]2 years ago
6 0
After looking at the transverse waves in the diagram you listed above, the one diagram that does represent the direction of particle X at the instant show in diagram number 3. The direction of the wave motion is up. The correct answer choice will be 3. 
vladimir2022 [97]2 years ago
6 0
<h3><u>Answer</u>;</h3>

(4) last diagram

<h3><u>Explanation</u>;</h3>
  • <em><u>A transverse wave is a type of wave where the movement of the particles of the medium is perpendicular to the direction of the propagation of the wave. </u></em>
  • Transverse waves forms regions of maximum displacement known as crests and troughs. The crests are the top points of the wave and the trough is the bottom point of the wave.
  • In a transverse wave particles of the medium vibrate to and from in a direction perpendicular to the direction of energy transport.
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An aircraft with a mass of 10,000 kg starts from rest at sea level and takes off, then flies to a cruising speed of 620 km/h and
Natasha_Volkova [10]

Answer:

The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

Explanation:

Given that,

Mass of aircraft = 10000 kg

Speed = 620 km/h = 172.22 m/s

Altitude = 10 km = 1000 m

We calculate the change in potential energy

\Delta P.E=mg(h_{2}-h_{1})

\Delta P.E=10000\times9.8\times(10000-0)

\Delta P.E=10000\times9.8\times10000

\Delta P.E=980000000\ J

\Delta P.E=980\ MJ

For g = 10 m/s²,

The change in potential energy will be 1000 MJ.

We calculate the change in kinetic energy

\Delta K.E=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2-0^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2)

\Delta K.E=148298642\ J

\Delta K.E=148.3\ MJ

For g = 10 m/s²,

The change in kinetic energy will be 150 MJ.

Hence, The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

7 0
2 years ago
Which kinds of objects emit visible light in the electromagnetic spectrum?
Triss [41]

Answer : Relatively hot objects

Explanation : We know that, the temperature of the objects is inversely proportional to their wavelengths. The objects emitting radiation in the visible region have short wavelength and hence are relatively hotter.

We know the range of wavelength of the visible spectrum is from 400 nm to 780 nm.





3 0
2 years ago
Read 2 more answers
A resistor, an inductor, and a switch are all connected in series to an ideal battery of constant terminal voltage. Suppose at f
Airida [17]

Answer:

c. The steady-state value of the current depends on the resistance of the resistor.

Explanation:

Since all the components are connected in series, when the switch is at first open, current will not flow round the circuit. As current needs to flow through from the positive terminal of the battery through the resistor, inductor, and  switch to the negative terminal of the battery.

But the moment the switch is closed, at the initial time t = 0, the current flow through from the positive terminal of the battery through the resistor, inductor, and switch to the negative terminal of the battery. It then begins to increase at a rate that depends upon the value of the inductance of the inductor.

6 0
2 years ago
HALP me!! This is a physics question.
emmasim [6.3K]
<h2>Answer:</h2>

<u>Distance covered is 6.9 meters</u>


<h2>Explanation:</h2>

Data given:

Work Done = 345 kJ = 345000 J

Force = 5 x 10 ^ 4 =  50000 N

Distance = ?


Solution:

As we know that

Work Done = Force applied x Distance covered

By arranging the equation we get

Work / Force = Distance covered

By putting the values

345000 / 50000 = 6.9

So distance covered is 6.9 meters

4 0
3 years ago
Read 2 more answers
Solve for the unknown in each of these circuits
Tamiku [17]

<u> Ohms law: </u> This law relates voltage difference between two points. Mathematically, the law states that V=IR;

                Where

                          V = voltage difference ; in volts

                          I = Current ; in Amperes

                          R = Resistance ; in ohms

<u>1. Answer : </u> given that R = 10 ; V= 12 V ;  I = ?

From ohms law,    I = V/R

                                = 12/10

                                = 1.2 Amp.

<u>2. Answer:</u>  given that R = 10 ; V= ? ;  I = 5

From ohms law,    V = IR

                                 = 10×5 = 50 V

<u>3 . Answer:</u>  given that R = ? ; V= 120 ;  I = 5

From ohms law,    R =  V/I

                                 = 120/5

                                 = 24 Ω

<u>4 . Answer:</u>  given that R = ? ; V= 10 ;  I = 20

From ohms law,    R =  V/I

                                 = 10/20

                                 = 0.5 Ω

<u>5 . Answer:</u>  given that R = 480 ; V= 24 ;  I = ?

From ohms law,  I =  V/R

                              = 24/480

                              = 0.05 A

<u>6. Answer:</u>  given that R = 150 ; V= ? ;  I = 1

From ohms law,  V = IR

                               = 1 × 150

                               = 150 V


6 0
3 years ago
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