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exis [7]
3 years ago
6

A transverse wave is moving toward the right in a uniform medium. Point X represents a particle of the uniform medium. Which dia

gram represents the direction of the motion of particle X at the instant shown?

Physics
2 answers:
trapecia [35]3 years ago
6 0
After looking at the transverse waves in the diagram you listed above, the one diagram that does represent the direction of particle X at the instant show in diagram number 3. The direction of the wave motion is up. The correct answer choice will be 3. 
vladimir2022 [97]3 years ago
6 0
<h3><u>Answer</u>;</h3>

(4) last diagram

<h3><u>Explanation</u>;</h3>
  • <em><u>A transverse wave is a type of wave where the movement of the particles of the medium is perpendicular to the direction of the propagation of the wave. </u></em>
  • Transverse waves forms regions of maximum displacement known as crests and troughs. The crests are the top points of the wave and the trough is the bottom point of the wave.
  • In a transverse wave particles of the medium vibrate to and from in a direction perpendicular to the direction of energy transport.
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<span>1/3 The key thing to remember about an elastic collision is that it preserves both momentum and kinetic energy. For this problem I will assume the more massive particle has a mass of 1 and that the initial velocities are 1 and -1. The ratio of the masses will be represented by the less massive particle and will have the value "r" The equation for kinetic energy is E = 1/2MV^2. So the energy for the system prior to collision is 0.5r(-1)^2 + 0.5(1)^2 = 0.5r + 0.5 The energy after the collision is 0.5rv^2 Setting the two equations equal to each other 0.5r + 0.5 = 0.5rv^2 r + 1 = rv^2 (r + 1)/r = v^2 sqrt((r + 1)/r) = v The momentum prior to collision is -1r + 1 Momentum after collision is rv Setting the equations equal to each other rv = -1r + 1 rv +1r = 1 r(v+1) = 1 Now we have 2 equations with 2 unknowns. sqrt((r + 1)/r) = v r(v+1) = 1 Substitute the value v in the 2nd equation with sqrt((r+1)/r) and solve for r. r(sqrt((r + 1)/r)+1) = 1 r*sqrt((r + 1)/r) + r = 1 r*sqrt(1+1/r) + r = 1 r*sqrt(1+1/r) = 1 - r r^2*(1+1/r) = 1 - 2r + r^2 r^2 + r = 1 - 2r + r^2 r = 1 - 2r 3r = 1 r = 1/3 So the less massive particle is 1/3 the mass of the more massive particle.</span>
8 0
3 years ago
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Ivanshal [37]

Light having a dual nature and acting like both a wave and a particle is the correct statement in this scenario.

<h3>What is Light?</h3>

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The dual nature of light is as a result of it behaving like a photon which is why it travels in straight lines.

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C, hope this helps!!!!!!!                                                                                  

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