Cholesterol is a sterol, it is a type of lipid molecule, and is biosynthesized by all animal cells. Total cholesterol level lesser than 200 milligrams per deciliter (mg/dL) is considered desirable for an adult. The standard unit used for any substance is gram per liter. However sometimes the concentration can also be expressed in terms of mg per deciliter. In this context 1 gram per liter is equal to 100 milligram per deciliter.
Thus 1.85 gram per liter is equal to 185 mg per deciliter. So 1.85 g/L is equivalent to 185mg per deciliter.
Answer:
0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM
Explanation:
An enzyme solution is saturated when all the active sites of the enzyme molecule are full. When an enzyme solution is saturated, the reaction is occurring at the maximum rate.
From the given information, an enzyme concentration of 1.0 μM Y can convert a maximum of 0.5 μM AB to the products A and B per second means that a 1.0 M Y solution is saturated when an AB concentration of 0.5 M or greater is present.
The addition of more substrate to a solution that contains the enzyme required for its catalysis will generally increase the rate of the reaction. However, if the enzyme is saturated with substrate, the addition of more substrate will have no effect on the rate of reaction.
<em>Therefore the reaction rates at substrate concentrations of 0.7μM, 0.6 μM, and 0.5 μM are equal. But the reaction rate at substrate concentrations of 0.2 μM is lower than at 0.3 μM, 0.3 μM is lower than 0.4 μM and 0.4 μM is lower than 0.5 μM, 0.6 μM and 0.7 μM.</em>
Answer:
when the red litmus paper is placed in a jar of ammonia, the red litmus paper turns into blue as ammonia gas is basic in nature. It confirms the alkalinity of the ammonia gas.
[CO] = 1 mol / 2L = 0.5 M
[
According to the equation:
and by using the ICE table:
CO(g) + H2O(g) ↔ CO2(g) + H2(g)
initial 0.5 0.5 0 0
change -X -X +X +X
Equ (0.5-X) (0.5-X) X X
when Kc = X^2 * (0.5-X)^2
by substitution:
1.845 = X^2 * (0.5-X)^2 by solving for X
∴X = 0.26
∴ [CO2] = X = 0.26
Answer:
mass of sulfur = 96 g
Explanation:
no of moles of sulfur dioxide in 
molecules = 
= 2 moles
therefore mass of sulfur dioxide = moles×atomic number
=2×(16+32)
=96
