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Goryan [66]
3 years ago
11

In a laboratory experiment, a fermenting aqueous solution of glucose and yeast produces carbon dioxide gas and ethanol. The solu

tion was heated by burning natural gas in a Bunsen burner to distill the ethanol that formed in the flask. During the distillation, the ethanol evaporated and then condensed in the receiving flask. The flame of the burner was kept too close to the bottom of the flask and some of the glucose decomposed into a black carbon deposit on the inside of the flask. During this experiment the following changes occurred. Which of these changes involved a physical change and not a chemical change?
1. evaporation of ethanol
2. condensation of ethanol
3. formation of a carbon deposit inside the flask
4. formation of carbon dioxide gas from glucose
5. burning of natural gas
6. formation of ethanol from glucose by yeast
Chemistry
1 answer:
Serggg [28]3 years ago
5 0

Answer:

1. evaporation of ethanol

2. condensation of ethanol

Explanation:

The first and second process imply a change of phase, which is essentially a  physical change because the matter change from liquid to gas and from gas to liquid respectively and it can ve reversed.

The options 3 to 6 are related to a chemical reaction because the outcomes of the process are different compounds than the ones we had at the beginning. The main reaction that implies process 3 to 6 is represented by:

C6H12O6 +  impurities → 2 C2H5OH + 2 CO+ C

For option 5. burning of natural gas , we have:

Natural gas(Mainly a mix of CH4 and C2H10) +O2→COn+H2O

Therefore, justo 1 and 2 are a physical change

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Answer:

See Explanation

Explanation:

The Law of Conservation of Matter as applied to chemical reactions says that matter is neither created nor distroyed, only changed in form. This implies that the mass of substances going into a reaction process must equal the mass of products generated during the reaction process.

Empirically,

∑ mass reactants = ∑ mass products

One can test this idea after balancing a chemical equation by determining the sum of formula weights of reactants and products; then compare. If reaction was properly balanced, the total mass reactants = total mass of products.

Example:

Combustion of Methane =>  CH₄(g) + 2O₂(g)   =>  CO₂(g) + 2H₂O(l)

Equation Weights =>             16amu + 64amu <=> 44amu +  36amu

Mass Reactants = Mass Products  => 80amu <=> 80amu.

__________________

*amu = atomic mass units => sum of atomic weights of elements

3 0
4 years ago
For the reaction COCl2(g)⇌CO(g)+Cl2(g), K= 2.19×10−10 at 373 K
vladimir1956 [14]

Answer:

D) The equilibrium lies far to the left

Explanation:

According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:

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([X] means = concentration of X)

This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.

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Answer:

Explanation:

It can be determined by measuring the Ph. D is incorrect.

C: is wrong because if you are making something acidic, you are increasing the H+

B: is the correct answer.

A: pH decreases. H+ increases which makes the Ph decrease. It is an oddity of the formula that makes this happen.

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