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vagabundo [1.1K]
3 years ago
12

Find the minimum uncertainty in the speed of a uranium nucleus having mass 4e-25 kg if we know the position of the uranium nucle

us to within 1e-14 m, that is, to about its own size.

Physics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

13180 m/s

Explanation:

Mass is a measure of the amount of matter in an object. Mass is usually measured in grams (g) or kilograms (kg)

The nucleus is a membrane-bound organelle that contains genetic material (DNA) of eukaryotic organisms. As such, it serves to maintain the integrity of the cell by facilitating transcription and replication processes.

Having understood those terms, lets calculate the minimum uncertainty in the speed of a uranium nucleus having mass 4e-25 kg if we know the position of the uranium nucleus to within 1e-14 m, that is, to about its own size.

Please kindly check attachment for the step by step explaination.

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Hi there!

We can begin by calculating the time the ball takes to reach the highest point of its trajectory, which can be found using the following:

t_{max} = \frac{vsin\theta}{g}

Where:

tmax = (? sec)

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g = acceleration due to gravity (9.8 m/s²)

We can solve for this time:

t_{max} = \frac{7.43}{9.8} = 0.758 s

When the ball is at the TOP of its trajectory, its VERTICAL velocity is equivalent to 0 m/s. Thus, we can consider this a free-fall situation.

We must begin by solving for the maximum height reached by the ball using the equation:

d = y_0 + v_{0y}t + \frac{1}{2}at^2

d = displacement (m)

vi = initial velocity (7.43 m/s)

a = acceleration due to gravity

d = displacement (m)

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Plug in the values:

d = 28 + 7.43(0.758) + \frac{1}{2}(-9.8)(0.758^2) = 30.817 m

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Add the two times together:

0.758 + 2.51 = \boxed{3.266 s}

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