On the generalized enthalpy departure chart, the normalized enthalpy departure values seem to approach zero as the reduced press
1 answer:
You might be interested in
Answer:
The force acting on the bullet
The value of impulse on the bullet in the given time interval P = 92.4
Explanation:
Mass of the bullet ( m ) = 200 gr = 0.028 lb
Initial velocity ( U ) = 0
Final Velocity ( V ) = 3300
Force acting on the bullet
⇒
⇒
This is the force acting on the bullet.
Magnitude of the impulse imparted on the bullet -------- (1)
Put the value of F & dt in above equation we get,
P = 84000 × 0.0011
P = 92.4
This is the value of impulse on the bullet in the given time interval.
Answer:
Speed=1.633 m/s
Force= 20 N
Explanation:
Ideally, hence
where v is the speed of collar, m is the mass of collar, k is spring constant and s is the displacement.
In this case, s=100-0=100mm=0.1m since 1 m is equivalent to 1000mm
k is given as 200 N/m and mass is 0.75 Kg
Substituting the given values
Therefore, <u>the speed is 1.633 m/s</u>
The sum of vertical forces is given by mg where g is acceleration due to gravity and it's value taken as
Therefore,
The sum of forces in normal direction is given by therefore
Therefore, <u>normal force on the rod is 20 N</u>