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Ronch [10]
3 years ago
10

2,231.5= how many grams?

Mathematics
2 answers:
svlad2 [7]3 years ago
4 0
What are you converting it to/from?
irina1246 [14]3 years ago
4 0
What is 2,231.5? ounces?
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AB = 6x DC = x + 15 AD = 9 BC = 3y Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent. Show tha
ra1l [238]

Answer:

Therefore the lengths of the opposite side pairs.

C) 18, 9

Step-by-step explanation:

Given:

Quadrilateral ABCD is a parallelogram

AB = 6x

DC = x + 15

AD = 9

BC = 3y

TO Find:

AB = ?

BC = ?

Solution:

Quadrilateral ABCD is a parallelogram ..........Given

∴ Both pairs of opposite sides of a Parallelogram are congruent.

∴ AB = DC   and AD = BC

substituting the values we get

6x=x+15\\6x-x=15\\5x=15\\x=\dfrac{15}{5}\\ x=3\\and\\9=3y\\y=\dfrac{9}{3}\\ y=3

substituting the x' and 'y' values we get

AB= 6\times 3=18\\and\\BC=3\times 3=9

Therefore the lengths of the opposite side pairs.

C) 18, 9

3 0
3 years ago
Create a 3rd degree polynomial function with one zero at three. Sketch a graph
DedPeter [7]

Answer:

f(x) =  {x}^{3}  - 9 {x}^{2}  + 27x - 27

Step-by-step explanation:

We want to create a third degree polynomial function with one zero at three.

In other words, we want to find a polynomial function with roots x=3 , multiplicity, 3.

Since x=3 is a solution, x-3 is the only factor that repeats thrice.

f(x) =  {(x - 3)}^{3}

We expand to get:

f(x) =  x( {x}^{2}  - 6x  + 9) - 3( {x}^{2}  - 6x + 9)

f(x) =  {x}^{3}  - 6 {x}^{2}  + 9x- 3 {x}^{2}   + 18x  - 27

This simplifies to:

f(x) =  {x}^{3}  - 9 {x}^{2}  + 27x - 27

See attachment for graph.

4 0
3 years ago
How many numbers can you make between 0-99 using exactly four 4s and the operation?
Montano1993 [528]
A lot of numbers and it really depends
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3 years ago
How much will it cost to get 4 tires if the 4th one is free
GarryVolchara [31]
You would have to pay for 3 tires
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Use the unit circle to find sec (-90)
andreyandreev [35.5K]

Using the unit circle, you can visualise the secant as follows:

  1. Draw the vertical line passing trough (1,0)
  2. Extend the radius until it meets this line at point P
  3. The length of OP is the secant of your angle.

Since -90 means that the radius points downwards, it means that the radius is vertical as well, and thus it never meets the vertical line through (1,0).

Thus, the secant is not defined at -90.

In fact, if we switch back to the function notation, we can confirm this claim, since we have

\sec(x)=\dfrac{1}{\cos(x)}\implies \sec(-90)=\dfrac{1}{\cos(-90)}=\dfrac{1}{0}

which is undefined.

4 0
3 years ago
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