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3 years ago

What are the two processes by which nitrogen can be fixed in soil

2 answers:

6 0

There are three ways nitrogen can be fixed to be useful for living things: Biologically: Nitrogen gas (N2) diffuses into the soil from the atmosphere, and species of bacteria convert this nitrogen to ammonium ions (NH4+), which can be used by plants.

densk [106]3 years ago

5 0

Answer:nitrification and assimilation

Explanation:

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(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of

gregori [183]

Detonation of nitroglycerin:

$4C_3H_5N_3O_9 ------\ \textgreater \ 12CO_2+6N_2+O_2+H_2O$

Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g

Moles = mass / molar mass = 3.184 g/ 227.0872 g/mol = 0.01402

the ratio between nitroglycerin and Carbon dioxide is 4 : 12
So, moles CO2 = 0.01402 x 12 / 4 =0.0420

the ratio between nitroglycerin and N2 is 4 : 6
moles N2 = 0.01402 x 6 / 4 =0.0841

the ratio between nitroglycerin and O2 is 4 : 1 
moles O2 = 0.01402 x 1 / 4 = 0.0035

the ratio between nitroglycerin and water is 4 : 1 
in the same way moles water = 0.005258 

total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758

0.130758 x 55 = 5.78 L 

Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g

6 0

3 years ago

True or False. Index Fossils are formed from organisms that were alive for short period of geologic time, are extinct, had hard

NemiM [27]

Answer:

Index fossil, any animal or plant preserved in the rock record of the Earth that is characteristic of a particular span of geologic time or environment.

Explanation:

True

6 0

3 years ago

Read 2 more answers

How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0 degrees Celsius to 80 degrees Celsius? (

lapo4ka [179]

The heat required to raise the temperature of a certain mass of sample to a specific temperature change, we use the formula mCpΔT where m is mass, Cp is the specific heat of the substance and ΔT is the temperature change. In this case, we substitute and form 1.25 g x 0.057 cal/g C *20 C equal to 1.425 calories.

7 0

3 years ago

Good science does not depend on interactions within the scientific community. True False

Aloiza [94]

I believe the answer is true

4 0

3 years ago

Read 2 more answers

1. Complete the following

Marat540 [252]

Answer:

$\large \boxed{\text{0.603 mol}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of O₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 18.1

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{18.1 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1005 mol C$_{6}$H$_{12}$O}_{6}$

b) Moles of O₂

$\text{Moles of O}_{2} =\text{0.1005 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol O}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.603 mol O}_{2}\\\\\text{The reaction requires $\large \boxed{\textbf{0.603 mol}}$ of oxygen}$

3 0

3 years ago