Select the correct answer.
1 answer:
You might be interested in
Missing figure and missing details can be found here:
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
</span>
Solution:
(a) The work done by the spring is given by
where k is the elastic constant of the spring and
is the stretch between the initial and final position. Since x1=-8 in=-0.203 m and x2=5 in=0.127 m, we have
(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
where the negative sign is given by the fact that
points in the opposite direction of the displacement of the cart, and where
therefore, the work done by the weight is
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
</span>
Solution:
(a) The work done by the spring is given by
where k is the elastic constant of the spring and
(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
where the negative sign is given by the fact that
therefore, the work done by the weight is
Answer:
θ = 20.9 rad
Explanation:
In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship
w = θ / t
θ = w t
if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians
suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system
w = 10 rpm
= 1,047 rads
let's calculate
θ = 1,047 20
θ = 20.9 rad