1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
balandron [24]
3 years ago
5

Select the correct answer.

Physics
1 answer:
tester [92]3 years ago
8 0

Answer:

30%

Explanation:

Total profit=$25000

Initial investment=$10000

Return on investment is given by

RoI=(Gain from investment-cost of investment)/cost of investment

RoI=\frac {25000-10000}{10000}\times 100=150%

RoI=150% but since it's over 5 years, we distribute for 5 years hence annual RoI=\frac {150}{5}=30%

Therefore, RoI=30%

You might be interested in
Which theory was first proposed by Albert Einstein? A. the theory of special relativity B. the theory of universal gravitation C
balu736 [363]

A. the theory of special relativity

6 0
3 years ago
Read 2 more answers
As the wavelength of A wave in a uniform medium increases, its speed will what?
viva [34]

The speed of a wave in a uniform medium doesn't depend on its wavelength.


8 0
3 years ago
A 7.75-l flask contains 0.482 g of hydrogen gas and 4.98 g of oxygen gas at 65°c. What is the partial pressure of oxygen in the
dimulka [17.4K]

Answer:

0.558 atm

Explanation:

We must first consider that both gases behaves like ideal gases, so we can use the following formula: PV=nRT

Then, we should consider that, whithin a mixture of gases, the total pressure is the sum of the partial pressure of each gas:

P₀ = P₁ + P₂ + ....

P₀= total pressure

P₁=P₂= is the partial pressure of each gass

If we can consider that each gas is an ideal gas, then:

P₀= (nRT/V)₁ + (nRT/V)₂ +..

Considering the molecular mass of O₂:

M O₂= 32 g/mol

And also:

R= ideal gas constant= 0.082 Lt*atm/K*mol

T= 65°C=338 K

4.98 g O₂ = 0.156 moles O₂

V= 7.75 Lt

Then:

P°O₂=partial pressure of oxygen gas=  (0.156x0.082x338)/7.75

P°O₂= 0.558 atm

3 0
3 years ago
A tiger runs one kilometer. The tiger does 15,000 J of work and has a total power output of 500 W. How many minutes does it take
defon
Power is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. <span>As is implied by the equation for </span>power<span>, a unit of </span>power <span>is equivalent to a unit of work divided by a unit of time. The formula would be as follows:

P = W/t 

We calculate as follows:

500 W = 15000 J / t
t = 30 s</span>
3 0
3 years ago
Which describes the correct energy conversion when a solar cell is used to light a street lamp?
Lady_Fox [76]
I think it's a solar power might seem strange or futuristic but it's already quite common place you might have a solar powered quartz watch on your wrist or solar powered pocket calculator
3 0
3 years ago
Read 2 more answers
Other questions:
  • A psychologist claiming that a client's personal experiences and viewpoint influence behavior more than events in reality is usi
    9·2 answers
  • Which of the following takes place in the combustion chamber of a gas turbine engine?
    10·2 answers
  • Pls explain the following equation...
    8·1 answer
  • PLEASE PLEASE PLEASE HELP!!!! WILL MARK BRAINILIEST!!!!!!!!!!!
    9·1 answer
  • If it requires 3.0 J of work to stretch a particular spring by 2.1 cm from its equilibrium length, how much more work will be re
    5·1 answer
  • What happens when the fuel in a car engine combustion?​
    7·1 answer
  • Oceanic water particles mainly move in circles; is this movement greater on the ocean's surface or below the surface? Explain yo
    11·1 answer
  • Which product forms from the synthesis reaction between calcium (Ca) and
    6·2 answers
  • Which of jupiter’s moons is the largest moon in the solar system?.
    15·1 answer
  • A 20kg object acceleration by a force of 200N with coefficient of kineticfriction is 0.4 what is acceleration of the object?​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!