Answer is: l<span>ayer A is the troposphere and Layer B is the stratosphere.
</span>Troposphere<span> is the lowest layer of </span><span>Earth's atmosphere.
</span>Stratosphere<span>is the second layer of </span>Earth's atmosphere<span>, above the </span>troposphere<span>, and below the </span><span>mesosphere.
</span>A weather balloon<span> </span><span> a </span>balloon<span> send back information on </span>atmospheric pressure<span>, </span>temperature<span>, </span><span>humidity.</span>
Hey there!
Molar mass CuSO4 = <span>159.609 g/mol
</span><span>Note that the molarity is in the enunciation of the issue, then the problem asks the mass of the solute :
Volume in liters of solution:
150 mL / 1000 => 0.15 L
</span><span>Calculation of quantity in Moles of the solute :
</span>
1 L ----------------- 0.300 M
0.15 L ------------ ( moles )
Moles CuSO4 = 0.15 * 0.300 / 1
Moles CuSO4 = 0.045 moles
Therefore :
1 mole CuSO4 --------------------- 159.609 g
0.045 moles CuSO4-------------- mass
mass = 0.045 * 159.609 / 1
mass = 7.182405 g of CuSO4
Water acts as an acid (donates H+) when it reacts with a stronger base, say sodium hydroxide. Water acts as a base (accepts H+) when it reacts with a stronger acid, say hydrochloric acid. If the medium is water, water, having a pH of 7, is considered neutral.
Answer: P = 7.1 atm
Explanation: For this problem we will use Combined Gas Law to solve for the new pressure. But never forget to convert the unit of temperature to Kelvin.
P1V1 /T1 = P2V2/ T2, Derive for P2.
P2 = P1V1T2 / T1V2
= 1.00 atm ( 3.00 L ) ( 323 K) / 273 K ( 0.50 L )
= 7.1 atm
Cancel out the units of L and K and the unit remains is in atm.