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Ulleksa [173]
3 years ago
6

The heat transfer surface area of a fin is equal to the sum of all surfaces of the fin exposed to the surrounding medium, includ

ing the surface area of the fin tip. Under what conditions can we neglect heat transfer from the fin tip?
Engineering
1 answer:
sasho [114]3 years ago
7 0

Answer:

The explanation according to the given query is summarized in the explanation segment below.

Explanation:

  • If somehow the fin has become too lengthy, this same fin tip temperature approaches the temperature gradient and maybe we'll ignore heat transmission out from end tips.
  • Additionally, effective heat transmission as well from the tip could be ignored unless the end tip surface is relatively tiny throughout comparison to its overall surface.
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A car accelerates from rest with an acceleration of 5 m/s^2. The acceleration decreases linearly with time to zero in 15 s, afte
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Answer: At time 18.33 seconds it will have moved 500 meters.

Explanation:

Since the acceleration of the car is a linear function of time it can be written as a function of time as

a(t)=5(1-\frac{t}{15})

a=\frac{d^{2}x}{dt^{2}}\\\\\therefore \frac{d^{2}x}{dt^{2}}=5(1-\frac{t}{15})

Integrating both sides we get

\int \frac{d^{2}x}{dt^{2}}dt=\int 5(1-\frac{t}{15})dt\\\\\frac{dx}{dt}=v=5t-\frac{5t^{2}}{30}+c

Now since car starts from rest thus at time t = 0 ; v=0 thus c=0

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\int \frac{dx}{dt}dt=\int (5t-\frac{5t^{2}}{30})dt\\\\x(t)=\frac{5t^{2}}{2}-\frac{5t^{3}}{90}+D

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thus in the first 15 seconds it covers a distance of

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Thus the total time it requires equals 15+3.33 seconds

t=18.33 seconds

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2 years ago
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