Answer:
$2 per pen
Step-by-step explanation:
mechanical pencils: 5.25
all pens: 8
5.25+8= $13.25
:)
81 degrees
1 degree = 2 pi / 360
81 degrees = 162 pi / 360
=9 pi / 20
L (arc) = radius x angle
= 10 x 9 pi / 20
90 pi /20
9/2 pi : D
The answer is D
Answer: The number is: "2 " .
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Explanation:
__________________________________________
Write the expression; which is an equation, as follows:
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" 4x <span>− 12 = 2(-x) " ; in which "x" represents "the number for which we shall solve" .
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Note:
If the "number" = "x" ; the "opposite of the number" = " -x " ;
</span>___________________________________________
Rewrite as: " 4x <span>− 12 = -2x " ;
</span>_____________________________________________
→ Add "12" ; & add "2x" ; to EACH SIDE of the equation:
4x − 12 + 12 + 2x = -2x + 12 + 2x ;
to get: 6x = 12 ;
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Now, divide each side of the equation by "6" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
____________________________________________________
6x / 6 = 12 / 6 ;
to get: x = 2 .
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Answer: The number is: "2 " .
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Let us check our answer, by plugging in "2" for "x" in our original equation:
_____________________________________________________
→ " 4x − 12 = 2(-x) " ;
Let us plug in "2" for "x" ; to see if the equation holds true; that is; if both side of the equation are equal; when "x = 2" ;
→ " 4(2) − 12 = ? 2(-2) ??
→ 8 − 12 = ? -4 ? ;
→ -4 = ? -4 ?? Yes!
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Answer:
Use the method for solving Bernoulli equations to solve the following differential equation.
StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half
Step-by-step explanation:
Use the method for solving Bernoulli equations to solve the following differential equation.
StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half
Answer:



Step-by-step explanation:
<u>Optimizing With Derivatives
</u>
The procedure to optimize a function (find its maximum or minimum) consists in
:
- Produce a function which depends on only one variable
- Compute the first derivative and set it equal to 0
- Find the values for the variable, called critical points
- Compute the second derivative
- Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum
We know a cylinder has a volume of 4
. The volume of a cylinder is given by

Equating it to 4

Let's solve for h

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

Replacing the formula of h

Simplifying

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

Rearranging

Solving for r

![\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%7D%7B%5Cpi%20%7D%7D%5Capprox%201.084%5C%20feet)
Computing h

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.
The minimum area is

