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Sonbull [250]
3 years ago
13

What is the strength of an electric field that will put a force of 1.28 x 10-15 N on a proton?

Physics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer: E =  7,490.6 N/C

Explanation:

If we have a field E, and a particle with a charge q, the force that the particle experiences is:

F = E*q

In this case, we know that the force is:

F = 1.2*10^(-15) N

And we know that the particle is a proton, where the charge of a proton is:

q = 1.602*10^(-19) C

Then we can replace these two values in the equation to get:

1.2*10^(-15) N = E*1.602*10^(-19) C

We just need to isolate E.

(1.2*10^(-15) N)/(1.602*10^(-19) C) = E

7,490.6 N/C = E

That is the strength of the electric field.

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What best describes white light as it travels through a prism? Check all that apply. The light slows down. The light bends in th
VMariaS [17]
The best statements that describe white light as it travels through a prism are:
<span>1. The light slows down.
2. The light bends in the prism.
3. Light reflects off of the surface of the prism. 
4. The white light breaks into its component colors.
Hope this helps!</span>
5 0
3 years ago
Read 2 more answers
If an object weighs 300 N on earth, what is it’s mass on the moon?
inna [77]

Answer:

The mass of the object on the Moon (and anywhere else) is about 30.61kg. Please see more detail below.

Explanation:

Weight is the gravitational force exerted on the object and is a function of mass and gravitational acceleration:

(weight) = (mass) x (gravitational acceleration)

We are to find the mass, knowing the weight on Earth to be 300N:

(mass) = (weight on Earth) / (gravitational acceleration on Earth) = 300N / 9.8 m/s^2 = 30.61 kg

The mass of the object is 30.61kg.

The mass of the object is independent of gravity. Therefore the answer to the question "What is its mass on the Moon" is 30.61kg.

If the question were what is its weight on the Moon, the answer would be

(weight on Moon) = (mass) x (grav.accel. on Moon) = 30.61kg x 1.62 m/s^2 = 49.59N

which is about 1/6 of the object's weight on the Earth.

4 0
3 years ago
A girl walks 5km due north,then in the direction of 60° of northeast towards her final destination.If the magnitude of her resul
storchak [24]

Answer:

4.2 km

Explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as isosceles triangle, scalene triangle, equilateral triangle and right angled triangle.

Sine rule states that for a triangle with angles A,B and C and corresponding opposite sides a, b, and c, the following formula holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

Let the starting point be A, hence the side opposite to the  angle = a = distance travelled in north east direction.

Let the point of 60° of northeast be B = 90° + (90° - 60°) = 120°, hence the side opposite to the  angle = b = resultant displacement = 8 km.

Let C be the endpoint, hence the side opposite to the  angle = c = distance travelled north = 5 km

Using sine rule:

\frac{b}{sin(B)}=\frac{c}{sin(C)}  \\\\\frac{8}{sin(120)}=\frac{5}{sin(C)}  \\\\sin(C)=\frac{5*sin(120)}{8} =0.5412\\\\C=sin^{-1}(0.5412)=32.8^o\\\\

∠A + ∠B + ∠C = 180° (sum of angle in a triangle)

∠A + 120 + 32.8 = 180

∠A = 27.2°

\frac{b}{sin(B)}=\frac{a}{sin(A)}  \\\\\frac{8}{sin(120)}=\frac{a}{sin(27.2)}  \\\\a=\frac{8*sin(27.2)}{sin(120)} \\\\a=4.2\ km

Therefore she travelled 4.2 km in the north east direction

5 0
3 years ago
what kind of wave would be observed in outer space between planets where there is very little matter?
ddd [48]
Shock waves can be observed in outer space between planets where there is very little matter. Although little, plasma does exist in outer space which allows the waves to travel.
5 0
3 years ago
While dragging a crate a workman exerts a force of 628 N. Later, the mass of the crate is increased by a factor of 3.8. If the w
Delvig [45]
Force applied = F = 628 N 
<span>Acceleration = a m/s² </span>
<span>Newton's 2nd law of motion : F = Ma </span>
<span> a = F/M -------- (1) </span>
<span>New mass of the crate = M1 = 3.8M kg </span>
<span>New acceleration = a1 = F/M1 = F/(3.8 M) ----- (2) </span>
<span>a1/a = {F/(3.8M)}/(F/M) = 1/3.8 = 10/38 = 5/19 ------- Answer</span>
6 0
4 years ago
Read 2 more answers
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