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kkurt [141]
2 years ago
13

Consider these reactions:

Chemistry
1 answer:
Virty [35]2 years ago
3 0

511.2 grams of chlorine gas consumed (with excess H-) when

1,342.0 kJ of energy is released from the system.

<h3></h3><h3>What is an exothermic reaction?</h3>

In thermochemistry, an exothermic reaction is a "reaction for which the overall standard enthalpy change ΔH⚬ is negative."

Given that 1 mole of chlorine releases -184.6 energy.

Then, we have to find the number of moles of chlorine when 1,342.0 kJ of energy is released from the system.

So, calculating number of moles of chlorine.

Moles = \frac{-1,342.0 \;kJ}{-184.6\;kJ}

Moles = 7.2 mole

Now, calculating number mass of chlorine.

\rm Moles=\rm\frac{Mass}{Molar \;mass}

Mass =  7.2 mole x 71 g/mole

Mass = 511.2 gram

Learn more about exothermic reaction here:

brainly.com/question/10373907

#SPJ1

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How many grams of hydrochloric acid are produced when 15.0 grams NaCl react with excess H2SO4 in the reaction
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Answer:

11.65 g

Explanation:

Amount of NaCl  = 15.0 grams

amount of H₂SO₄ = Excess

mass of hydrochloric acid (HCl) = ?

Solution:

To solve this problem first we will look for the reaction that NaCl react with  H₂SO₄

Reaction:

         2NaCl + H₂SO₄ --------> 2 HCl + Na₂SO₄

As the  H₂SO₄ is in excess so the amount of hydrochloric acid (HCl) depends on the amount of NaCl as it its act as limiting reactant.

Now if we look at the reaction

         2NaCl + H₂SO₄ --------> 2HCl + Na₂SO₄

           1 mol                              2 mol  

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Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

So,

            2NaCl           +      H₂SO₄     -------->       2HCl        +     Na₂SO₄

      2 mol (58.5 g/mol)                                    2 mol (36.5 g/mol)

              94 g                                                           73 g

So if we look at the reaction; 94 g of NaCl gives with 73 g of hydrochloric acid (HCl) in a this reaction, then how many grams of hydrochloric acid (HCl) will produce from 15.0 g of NaCl

For this apply unity formula

           94 g of NaCl  ≅ 73 g of HCl

           15.0 g of NaCl  ≅ X g of HCl

By Doing cross multiplication

           X g of HCl = 73 g x 15.0 g / 94 g

           X g of HCl = 11.65 g

11.65 g of hydrochloric acid (HCl) will produce by 15.0 g of NaCl

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