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kkurt [141]
2 years ago
13

Consider these reactions:

Chemistry
1 answer:
Virty [35]2 years ago
3 0

511.2 grams of chlorine gas consumed (with excess H-) when

1,342.0 kJ of energy is released from the system.

<h3></h3><h3>What is an exothermic reaction?</h3>

In thermochemistry, an exothermic reaction is a "reaction for which the overall standard enthalpy change ΔH⚬ is negative."

Given that 1 mole of chlorine releases -184.6 energy.

Then, we have to find the number of moles of chlorine when 1,342.0 kJ of energy is released from the system.

So, calculating number of moles of chlorine.

Moles = \frac{-1,342.0 \;kJ}{-184.6\;kJ}

Moles = 7.2 mole

Now, calculating number mass of chlorine.

\rm Moles=\rm\frac{Mass}{Molar \;mass}

Mass =  7.2 mole x 71 g/mole

Mass = 511.2 gram

Learn more about exothermic reaction here:

brainly.com/question/10373907

#SPJ1

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To identify minerals

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6 0
3 years ago
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[ 1.3 ] What is the concentration (%) of solute in the RBC (i.e., what is the concentration of all solute molecules combined?) A
ch4aika [34]

Answer:

0.9%

Explanation:

At the instance where you add RBCs to a solution of 0.9% NaCl, they will maintain their shape as well as their size, this is simply to indicate an equilibrium. That entails that the solution is isotonic to the RBCs. This must mean that the concentration of solutes on each side must be equal otherwise osmotic pressure would force water either in or out of the membrane. Therefore, one can also safely assume that RBC's also have a solute concentration of 0.9%.

3 0
3 years ago
N2 + 3H2 mc011-1.jpg 2NH3<br> What is the mole ratio of hydrogen to ammonia?
hjlf
1 N₂ + 3 H₂ = 2 NH₃

Mole  ratio <span> of hydrogen to ammonia :

3 moles H</span>₂  :  2 moles NH₃   or  3 : 2

hope this helps!
3 0
3 years ago
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The atom as a whole<br> doesn’t carry any electric charge. It’s called a ____________ _________.
olchik [2.2K]

Answer:

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5 0
3 years ago
Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an
miv72 [106K]

Explanation:

The given data is as follows.

         Refractive index of mixture = 1.456

        Refractive index of hexane = 1.375

        Refractive index of toulene = 1.497

Let mole fraction of hexane = x_{1}

and, mole fraction of toulene = x_{2}

Also,        x_{1} + x_{2} = 1

or,            x_{1} = 1 - x_{2}

Hence, calculate the mole fraction of hexane as follows.

        refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.

              1.456 = (1 - x_{2}) \times 1.375 + x_{2} \times 1.497

               1.456 = 1.375 - 1.375x_{2} + 1.497x_{2}

               0.081 = 0.122x_{2}

                   x_{2} = \frac{0.081}{0.122}

                                = 0.66

Since,     x_{1} = 1 - x_{2}

                          = 1 - 0.66

                          = 0.34

Thus, we can conclude that mole fraction of hexane in your sample is 0.34.        

3 0
3 years ago
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