Hi there!
We can use IMPULSE to solve.
Recall impulse:
![I = \Delta p = m\Delta v = m(v_f - v_i)](https://tex.z-dn.net/?f=I%20%3D%20%5CDelta%20p%20%3D%20m%5CDelta%20v%20%3D%20m%28v_f%20-%20v_i%29)
Begin by calculating the impulse. Assuming up to be the + direction, and down to be the - direction.
![I = 68(11 - (-14)) = 68 \cdot 25 = 1700 kg\frac{m}{s}](https://tex.z-dn.net/?f=I%20%3D%2068%2811%20-%20%28-14%29%29%20%3D%2068%20%5Ccdot%2025%20%3D%201700%20kg%5Cfrac%7Bm%7D%7Bs%7D)
Now, we can calculate force using this value:
![I = F \cdot t\\\\F = \frac{I}{t}\\\\F = \frac{1700}{0.85} = \boxed{2000 N}](https://tex.z-dn.net/?f=I%20%3D%20F%20%5Ccdot%20t%5C%5C%5C%5CF%20%3D%20%5Cfrac%7BI%7D%7Bt%7D%5C%5C%5C%5CF%20%3D%20%5Cfrac%7B1700%7D%7B0.85%7D%20%3D%20%5Cboxed%7B2000%20N%7D)
<u>The weight experiences a net force of 2000N UPWARDS.</u>
(2)(3)(2)=12⇒ D=M/V ⇒ D=94/12=7.8333(repeated) g/m³
Answer:
radian
Explanation:
We are given that
Wavelength=![\lambda](https://tex.z-dn.net/?f=%5Clambda)
We have to find the phase difference when the wavelength is equal to half of the initial wavelength.
Path difference=![\Delta x=\frac{\lambda}{2}](https://tex.z-dn.net/?f=%5CDelta%20x%3D%5Cfrac%7B%5Clambda%7D%7B2%7D)
For interference
Phase difference=![\frac{2\pi}{\lambda}\times \Delta x](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%7D%7B%5Clambda%7D%5Ctimes%20%5CDelta%20x)
Substitute the value
Phase difference=![\frac{2\pi}{\lambda}\times\frac{\lambda}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%7D%7B%5Clambda%7D%5Ctimes%5Cfrac%7B%5Clambda%7D%7B2%7D)
Phase difference=
radian
Answer:
Well, temperature is simply an average measure of the kinetic energy for particles of matter. Another way of putting it would be that temperature simply describes the average vibration of particles. Because the motion of all particles is random, they don’t all move at the same speed and in the same direction.