Answer:
697 g / mol
Explanation:
The osmotic pressure of a protein ( non electrolyte ) is given by:
π V= nRT where V is the volume, n is the number of moles, R is the gas constant ( 0.08206 L·atm/Kmol ), and T is the temperature (K).
n= mass/ MW protein ⇒ MW protein = mass / n
Thus,
π V = ( mass/ MW ) RT
MW = mass x R xT/ ( π V )
mass = 0.873 g
R = 0.08206 L·atm/K·mol
T = ( 15.6 + 273 ) K= 288.6 K
π = 0.061 atm
V = 48.6 mL = 48.6 mL x ( 1 L/ 1000 mL ) = 0.0486 L
We just need to plug our values into the aqbove equation for MW:
MW = 0.873 g x 0.08205 L· atm /K·mol x 288.6 K / ( 0.061 atm x0.0486 L )
= 697 g/mol
