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lisov135 [29]
3 years ago
10

Light is an oscillating electric field alone. an oscillating electric field and a fluctuating magnetic field that are parallel t

o each other. an oscillating electric field and a fluctuating magnetic field that are oriented randomly with respect to each other. an oscillating electric field and a fluctuating magnetic field that are perpendicular to each other. a fluctuating magnetic field alone.
Physics
1 answer:
Kaylis [27]3 years ago
6 0

Answer:

d) True  light is the two fluctuating perpendicular fields

Explanation:

When we solve Maxwell's equations for this system, it results in a traveling wave that is perpendicular to the two fields.

Let's analyze the affirmations

a) False. The light needs both fields

b) False violates Lenz's law

c) False. The two fields are perpendicular

d) True two fluctuating perpendicular fields

e) Falos needs both fields

Correct answer d)

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We need to find the average speed of the ball during the motion of 1 m

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t1 = 2.26 s

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t4 = 2.26 s

t5 = 2.31 s

Now in order to find the average time we can write

T_{mean} = \frac{t_1 + t_2 + t_3 + t_4 + t_5}{5}

T_{mean} = \frac{2.26 + 2.38 + 3.02 + 2.26 + 2.31}{5}

T_{mean} = 2.45 s

So average time to cover the distance of 1 m by ball will be 2.45 s

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4 years ago
A box (FW = 20 N) is placed on a ramp with a 60° incline. Which of these is an expression for the component of the weight parall
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4 0
3 years ago
A is a process that involves reactants and products
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4 years ago
A 780 g , 54-cm-long metal rod is free to rotate about a frictionless axle at one end. While at rest, the rod is given a short b
evablogger [386]

Answer:

The angular velocity is <em>35.5 rad/s.</em>

Explanation:

Step 1: Find the moment of Inertia for the rod

The moment of inertia, <em>I</em>, of a rod:

<em>I=\frac{1}{12} ML^{2} .......... (1)</em>

where M = mass of rod (0.78 Kg); L = Length of rod (0.54 m).

I=\frac{1}{12} (0.78)(0.54)^{2} =0.019\frac{Kg}{m^{2} }

Step 2: Calculate the angular acceleration from Rotational kinetic notation

<em>F.r = I.α ........... (2)</em>

<em>where F is the force acting upon the rod; r is the half length of the rod; I is the moment of Inertia and; α is the angular acceleration.</em>

<em>∴ (1000 N)(0.27 m) = 0.019α</em>

<em>α = 270 Nm / 0.019 Kgm²</em>

<em>α = 14210.5 rad/s</em>

Step 3: We find the angular velocity by using the equation below:

<em>ωf = ωi + αt ......... (3)</em>

<em>where </em>

<em>ωf is the angular velocity after the blow</em>

<em>ωi is the angular velocity before the blow = 0</em>

<em>t is the time taken for the blow to occur = 2.5 ms</em>

<em>ωf = 0 + (14210.5 rad/s)(2.5 ms) = 35.5 rad/s.</em>

<em />

6 0
3 years ago
The full moon rises in the east at the time of sunset. After rising, it continuously moves to the west and is seen high in the s
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Answer:

Earth rotates from West to East on its own axis. As a result of this, the Moon changes its position during the night and the Moon appears to move from East to West in the sky.

Explanation:

6 0
3 years ago
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