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3 years ago

How many bonds does carbon atom form

Chemistry

2 answers:

Neporo4naja [7]3 years ago

6 0

Answer: Four Bonds

Explanation:

coldgirl [10]3 years ago

6 0

A carbon atom can form at max four bonds, for example with Hydrogen. Since carbon has 4 electrons, it needs four more electrons to achieve the noble gas state. Carbon needs four more hydrogens, which has one electron, to bond four bonds

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Ivanshal [37]

200rates

sana ay makatulong hehehe <3

3 0

3 years ago

15 Points. Pls give a real answer this is due in an hour.

bonufazy [111]

Answer:

This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.

7 0

3 years ago

Imagine a planet that has a similar atmospheric pressure to Earth (760 mmHg) but different concentrations of gases in its atmosp

RUDIKE [14]

Answer:

76 mmHg is the partial pressure of oxygen on this new planet.

Explanation:

Atmospheric pressure on air on earth = 760 mmHg

On an unknown planet :

Oxygen makes up 10% of the atmosphere.

The mole fraction of oxygen gas can be written as = $\chi_1=\frac{10}{100}=0.1$

Carbon dioxide makes up 15% of the atmosphere.

The mole fraction of carbon dioxide gas can be written as = $\chi_2=\frac{15}{100}=0.15$

Nitrogen makes up the remaining 75% of the atmosphere.

The mole fraction of nitrogen gas can be written as = $\chi_1=\frac{75}{100}=0.75$

Atmospheric pressure of air on unknown planet,p= 760 mmHg (given)

Partial pressure of gases can be calculated by the help o Dalton's law of partial pressure:

Partial pressure of oxygen gas :

$p_1=p\times \chi_1$

$p_1=760 mmHg\times 0.1=76 mmHg$

Partial pressure of carbon dioxide gas :

$p_2=p\times \chi_2$

$p_2=760 mmHg\times 0.15=114 mmHg$

Partial pressure of nitrogen gas :

$p_3=p\times \chi_3$

$p_3=760 mmHg\times 0.75=570 mmHg$

8 0

3 years ago

1. Three

Bess [88]

Answer:

Explination:

Given Data:

Trail 1 Trial 2 Trial 3

Student A 448.0 cm 485.6 cm 463.4 cm

Student B 450.5 cm 441.3 cm 446.8 cm

Student C 422.6 cm 445.2 cm 432.7 cm

Accepted Value = 435.0 cm

Required:

A: Accurate measurement =?

B: Reason for the answer =?

C: Precise measurement =?

D: Reason for the answer =?

Solution:

Student A:

Trail 1: 435.0 cm – 448.0 cm = (13.0 cm greater than accepted value)

Trail 2: 435.0 cm – 485.6 cm = (50.6 cm greater than accepted value)

Trial 3: 435.0 cm – 463.4 cm = (28.4 cm greater than accepted value)

Student B:

Trail 1: 435.0 cm – 450.5 cm = (14.5 cm greater than accepted value)

Trail 2: 435.0 cm – 441.3 cm = (6.3 cm greater than accepted value)

Trial 3: 435.0 cm – 446.8 cm = (11.8 cm greater than accepted value)

Student C:

Trial 1: 435.0 cm – 422.6 cm = (12.4 cm less than accepted value)

Trial 2: 435.0 cm – 445.2 cm = (10.2 cm greater than accepted value)

Trial 3: 435.0 cm – 432.7 cm = (1.3 cm less than accepted value)

A: The 3rd trial of the student C is accurate measurement = 432.7 cm.

B: The 3rd value of students’ C measurement is accurate because it is quite near to the accepted value, i.e. 435.0 cm.

As we know that Accuracy refers to the closeness of a measured value to a standard or known value.

This value has only the difference of 1.3 cm.

435.0 cm – 432.7 cm = (1.3 cm less than accepted value)

All the other have larger difference which is as above.

___________________

Student A:

1. 448.0 cm – 485.6 cm = (37.6 cm far)

2. 485.6 cm – 463.4cm = (22.2 cm far)

Student B:

1. 450.5 cm – 441.3 cm = (9.2 cm far)

2. 441.3 cm – 446.8 cm = (5.5 cm far)

Student C:

1. 422.6 cm – 445.2 cm = (22.6 cm far)

2. 445.2 cm – 432.7cm = (12.5 cm far)

So,

C: The values of Student B are more precise.

D: As we know that Precision refers to the closeness of two or more measurements to each other.

The measurements of student C are more close to each other. The values are only 9.2 cm and 5.5 cm far from each other.

5 0

4 years ago

Calculate the energy needed to raise the temperature of 42 grams of water from 25.0 degrees Celsius to 48 degrees Celsius. The s

7nadin3 [17]

Answer:

option B is the answer.

B. 8266 calories

4 0

3 years ago

Read 2 more answers