All categories

3 years ago

A piece of magnesium metal is heated in the presence of chlorine gas, and a reaction takes place. What compound will most likely

Chemistry

1 answer:

Luba_88 [7]3 years ago

8 0

Answer:

Explanation:

magnesium + chlorine arrow magnesium chloride.

Mg(s) + Cl2(g) = MgCl2(s)

You might be interested in

A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

3 years ago

SO2+02➡SO3 balance chemical equation

Slav-nsk [51]

Answer:

2S02 + O2 ---> 2SO3

Its balanced now as Reactants = Products.

8 0

2 years ago

What properties of matter are intensive independent of their size

Paha777 [63]

Answer:

temperature, refractive index, density, and hardness of an object

Explanation:

it is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system

8 0

3 years ago

Please help. Thank you:)

bearhunter [10]

These are guesses because there is no word bank or anything

A. Water
B. Housing
C. Plants
D. Animals
E. Warmth

5 0

3 years ago

In this prelab exercise, you will calculate how to prepare solutions that you will make in lab. Below is an example of how to pr

Anastasy [175]

Explanation:

$Molarity=\frac{\text{Moles of compound}}{\text{Volume of solution (L)}}$

Moles of compound =

$\frac{\text{mass of compound}}{\text{Molar mass of compound}}$

We have ;

Volume of solution = 600 mL = 0.600 L ( 1 mL = 0.001 L)

Moles of NaOH = n

Molarity of the solution = 3 M

$3M=\frac{n}{0.600 L}$

n = 3 M × 0.600 L = 1.800 mol

Mass of 1.800 mole sof NaOH :

1.800 mol × 40 g/mol = 72.0 g

Preparation:

Weight 72.0 grams of sodium hydroxide and add it to the 500 mL of volumetric flask along with some water. Dissolve the all the solute by adding small proportion of water. After the solution becomes clear make the water upto the mark of 500 ml.

Transfer the solution to a bigger beaker and 100 mL of water more to it.

6 0

3 years ago