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BaLLatris [955]
3 years ago
7

Which of the following are medical applications of radiation? Select all that apply. cancer therapy detect and locate cancer gen

etic engineering increase growth rate detect thyroid malfunction pain relief
Chemistry
2 answers:
attashe74 [19]3 years ago
8 0

Answer:

The correct answer is cancer therapy, genetic engineering, and detecting thyroid malfunction.

Explanation:

There are numerous applications of radiation in medicine. The most well-known is the use of X-rays. Other than that radiations are also used in the treatment of cancer known as cancer therapy. It is also used in nuclear medicine therapy like the application of radioactive iodine in the treatment of thyroid issues like thyroid cancer. Radiation also has an application in genetic engineering that comprises the production of modifications in the hereditary units of prevailing animals and plants.

katrin [286]3 years ago
7 0

Answer:

The correct answer is cancer therapy, genetic engineering, and detecting thyroid malfunction.

Explanation:

There are numerous applications of radiation in medicine. The most well-known is the use of X-rays. Other than that radiations are also used in the treatment of cancer known as cancer therapy. It is also used in nuclear medicine therapy like the application of radioactive iodine in the treatment of thyroid issues like thyroid cancer. Radiation also has an application in genetic engineering that comprises the production of modifications in the hereditary units of prevailing animals and plants.

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What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas a
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144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

<h3>What is Ideal Gas Law ? </h3>

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Presure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = temperature in Kelvin

Here,

P = 1 atm  [At STP]

R = 0.0821 atm.L/mol.K

T = 273 K  [At STP]

Now first find the number of moles

F₂  +  CaBr₂  →  CaF₂  +  Br₂

Here 1 mole of F₂ reacts with 1 mole of CaBr₂.

So,  199.89 g CaBr₂ reacts with  = 1 mole of F₂

1.28 g of CaBr₂ will react with = n mole of F₂

n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}

n = 0.0064 mole

Now put the value in above equation we get

PV = nRT

1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K

V = 0.1434 L

V ≈ 144 mL

Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

Learn more about the Ideal Gas here: brainly.com/question/20348074

#SPJ4

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VLD [36.1K]

Answer:

0.36 m/s

Explanation:

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