Is oxigen a Molecule or a compound

The oceans level is currently rising at about 2 mm per year at this rate in how many years will sea level be 3 m higher than now

lesantik [10]

(3 m) / (2 mm/yr) = (3,000mm)/(2mm/yr) = 1,500 yrs.
This is the time required to age approx 75 generations of the best wine.

5 0

3 years ago

A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be ove

jonny [76]

We must remember that the total net force equation at constant velocity is:

F – Ff = 0

of

F - µN = 0

Using Newton's 2nd Law of Motion:

F = m a

Where,

F = net force acting on the body
m = mass of the body
a = acceleration of the body

Since the cart is moving at a constant velocity, then acceleration is zero, hence the working equation simplifies to

F = net Force = 0

Therefore,

F - µN = 0

where

µ = coefficient of friction = 0.20
N = normal force acting on the cart = 12 N

Therefore,

F - 0.20(12) = 0

F = 2.4 N

4 0

3 years ago

You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. Both strike the wall at speed v, but while the

lana [24]

Answer:

The fifth option is the correct answer: mv; 2 mv

Explanation:

Change of Momentum

Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is

$\Delta p=p_2-p_1$

The momentum is computed as

$p=mv$

Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.

The clay has an initial speed v and a mass m, thus its initial momentum is

$p_1=mv$

When it hits the wall, it sticks, thus its final speed is 0 and

$p_2=0$

The change of momentum is

$\Delta p=0-mv=-mv$

The absolute change is mv

Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is

$p_2=-mv$

The change of momentum is

$\Delta p=-mv-mv=-2mv$

The absolute change is 2mv

The fifth option is the correct answer: mv; 2 mv

3 0

3 years ago

A bicyclist passing through a city accelerates after he passes the sign post marking the city limits at x=0. His acceleration is

Anni [7]

Answer:

A. 24 m, 14 m/s

B. 8.0 m

Explanation:

Given:

x₀ = 6.0 m

v₀ = 4.0 m/s

a = 5.0 m/s²

t = 2.0 s

A. Find: x and v

x = x₀ + v₀ t + ½ at²

x = (6.0 m) + (4.0 m/s) (2.0 s) + ½ (5.0 m/s²) (2.0 m/s)²

x = 24 m

v = at + v₀

v = (5.0 m/s²) (2.0 s) + (4.0 m/s)

v = 14 m/s

B. Find x when v = 6.0 m/s.

v² = v₀² + 2a (x − x₀)

(6.0 m/s)² = (4.0 m/s)² + 2 (5.0 m/s²) (x − 6.0 m)

x = 8.0 m

8 0

3 years ago

A 2 N and an 8 N force pull on an object to the right and a 4 N force pulls to the left a 0.5 kg object. What is the acceleratio

lara31 [8.8K]

Answer:

Acceleration is 12m/s^2

Explanation:

We have a resultant force of 10N to the right and a resultant of 4N to the left, since the tow forces are acting in opposite directions, we subtract the two forces to find the net force. The net force would be 6N to the right.

We also know that F=ma, where F=force, m=mass, and a=acceleration

we can rearrange the equation like this,

a=F/m

now we can plug in the known variables

a=6N/0.5kg

a=12m/s^2

8 0

2 years ago