Answer:
The frequency of the oscillation is 2.45 Hz.
Explanation:
Given;
mass of the spring, m = 0.5 kg
total mechanical energy of the spring, E = 12 J
Determine the spring constant, k as follows;
E = ¹/₂kA²
kA² = 2E
k = (2E) / (A²)
k = (2 x 12) / (0.45²)
k = 118.519 N/m
Determine the angular frequency, ω;

Determine the frequency of the oscillation;
ω = 2πf
f = (ω) / (2π)
f = (15.396) / (2π)
f = 2.45 Hz
Therefore, the frequency of the oscillation is 2.45 Hz.
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Organ system is the correct response hope this helps
Answer: Final temperature of a gold nugget will be 297 K
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

q = heat released = -4.85 kJ = -4850 J
m = mass of metal = 376 g
= final temperature of metal = ?
= initial temperature of metal = 398 K
c = specific heat of metal =



Thus the final temperature of a gold nugget will be 297 K