<h3>
Answer:</h3>
117.6 Joules
<h3>
Explanation:</h3>
<u>We are given;</u>
- Force of the dog is 24 N
- Distance upward is 4.9 m
We are required to calculate the work done
- Work done is the product of force and distance
- That is; Work done = Force × distance
- It is measured in Joules.
In this case;
Force applied is equivalent to the weight of the dog.
Work done = 24 N × 4.9 m
= 117.6 Joules
Hence, the work done in lifting the dog is 117.6 Joules
Answer:
the answer is d
Explanation:
you get exhausted at the middle because it is steep.
Answer:
27.5 days
0.92 month
Explanation:
= radius of the orbit of moon around the earth = 
= Mass of earth = 
= Time period of moon's motion
According to Kepler's third law, Time period is related to radius of orbit as

inserting the values, we get

we know that
1 day = 24 hours = 24 x 3600 sec = 86400 s

1 month = 30 days
