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3 years ago

Name two fluid technologies that make use of water

Chemistry

2 answers:

labwork [276]3 years ago

6 0

I googled it and someone said fire extinguisher and a refridgerator ...

polet [3.4K]3 years ago

3 0

Answer:

Fire extenguisher and refrigerator

Explanation:

Refrigerator : There are 5 basic components in refrigeration I.e. fluid refrigerant, a compressor which controls the flow of refrigerant; the condensor coil( on the outside of the fridge), evaporation coils( on the inside of the fridge) and something calls an expansion device.

The compressor constricts the refrigerant vapour,raising its pressure and pushes it in the coils on the outside of the refrigerator.
When the hot gas in the coils meets the cooler air temperature of the kitchen it becomes a liquid.
Now in the liquid form at high pressure, the refrigerant cools down as it flows into the coils inside the freezer and the fridge.
The refrigerant absorbs the heat inside the fridge cooling down the air.
Last the refrigerant evaporates to a gas then flows back to the compressor where the cycle starts all over.

Fire Extinguishers: Water performs two functions; its conversion tosteam absorbs the heat, and the steam displaces the air from the vicinity of the flame. Many siimple fire extinguishers are quipped with hand pumps or sources of compressed gas to propel water through the nozzle.

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A piece of metal has a mass of 500 g and a volume of 5 cm3. What is its specific gravity?

Vadim26 [7]

I believe the answer is 100. Hope this helps. (ﾉ◕ヮ◕)ﾉ*:･ﾟ✧
density = mass/volume.

3 0

3 years ago

Sodium azide, NaN3, the explosive compound found in automobile air bags, decomposes according to the following equation: 2NaN3(s

shutvik [7]

Answer:

1.9 × 10² g NaN₃

1.5 g/L

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles of N₂ formed

N₂ occupies a 80.0 L bag at 1.3 atm and 27 °C (300 K). We will calculate the moles of N₂ using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.3 atm × 80.0 L / (0.0821 atm.L/mol.K) × 300 K = 4.2 mol

We can also calculate the mass of nitrogen using the molar mass (M) 28.01 g/mol.

4.2 mol × 28.01 g/mol = 1.2 × 10² g

Step 3: Calculate the mass of NaN₃ needed to form 1.2 × 10² g of N₂

The mass ratio of NaN₃ to N₂ is 130.02:84.03.

1.2 × 10² g N₂ × 130.02 g NaN₃/84.03 g N₂ = 1.9 × 10² g NaN₃

Step 4: Calculate the density of N₂

We will use the following expression.

ρ = P × M / R × T

ρ = 1.3 atm × 28.01 g/mol / (0.0821 atm.L/mol.K) × 300 K = 1.5 g/L

5 0

2 years ago

Calculate the molar solubility of PbBr2 (Ksp = 4.67x10-6) in 0.10M NaBr solution.

Softa [21]

Explanation:

$PbBr_{2}$ will dissociate into ions as follows.

$PbBr_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Br^{-}(aq)$

Hence, $K_{sp}$ for this reaction will be as follows.

$K_{sp} = [Pb^{2+}][Br^{-}]^{2}$

We take x as the molar solubility of $PbBr_{2}$ when we dissolve x moles of solution per liter.

Hence, ionic molarities in the saturated solution will be as follows.

$[Pb^{2+}]$ = $[Pb^{2+}]_{o}$ + x

$[Br^{-}]^{2}$ = $[Br^{-}]_{o}$ + 2x

So, equilibrium solubility expression will be as follows.

$K_{sp}$ = $([Pb^{2+}]_{o} + x)([Br^{-}]_{o} + 2x)^{2}$

Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains $[Br^{-}]_{o}$ = 0.10 and there will be no lead ions. So, $[Pb^{2+}]_{o}$ = 0

So, $[Br^{-}]_{o} + 2x$ will approximately equals to $[Br^{-}]_{o}$ .

Hence, $K_{sp} = x[Br^{-}]^{2}_{o}$

$4.67 \times 10^{-6} = x \times (0.10)^{2}$

x = $4.67 \times 10^{-4}$ M

Thus, we can conclude that molar solubility of $PbBr_{2}$ is $4.67 \times 10^{-4}$ M.

5 0

3 years ago

Read 2 more answers

What is the conjugate acid of hydroxylamine??

andrey2020 [161]

The conjugate acid of hydroxylamine it means, CHEBI:15429<span> </span><span>is conjugate acid of </span>aminooxidanide, it means CHEBI:29773.

6 0

2 years ago

What is the correct equilibrium constant expression for equation P2(g)

sertanlavr [38]

Answer:

k = [F2]² [PO]² / [P2] [F2O]²

Explanation:

In a chemical equilibrium, the equilibrium constant expression is written as the ratio between the molar concentration of the products over the molar concentration of the reactants. Each species powered to its reaction coefficient. For the equilibrium:

P2(g) + 2F2O(g) ⇄ 2PO(g) + 2F2(g)

The equilibrium constant, k, is:

k = [F2]² [PO]² / [P2] [F2O]²

6 0

3 years ago