We have that the maximum height reached by the basketball from its release point is
From the question we are told
- A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.
- What is the maximum height reached by the basketball from its release point?
Generally the Newtons equation for Motion is mathematically given as
Therefore
The maximum height reached by the basketball from its release point is
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Answer:
The power transmitted to the pulley is 0.0455 hp.
Explanation:
Given;
mass attached to the rope, m = 5 lb
radius of the pulley, r = 3 in
constant rate of fall of the mass, v = 5 ft/s
acceleration due to gravity, g = 32.2 ft/s²
1 lbf = 32.2 lb.ft/s²
The power transmitted to the pulley is calculated as;
P = Fv
P = (mg)v
in horse power, the power transmitted is calculated as;
Therefore, the power transmitted to the pulley is 0.0455 hp.
Answer:
answer is 10km
Explanation:
use "S =Ut "
S=distance U=velocity t =time
no need to convert time into seconds as the velocity has given in meters per minute
Answer:
The density of the box is 0.15 g/cm³
Explanation:
Given;
mass of the box, m = 15 g
dimension of the box, = 10 cm by 5 cm by 2 cm
Volume of the box, v = 10 cm x 5 cm x 2 cm = 100 cm³
The density of the box is given by;
Density = mass / volume
Density = 15 g / 100 cm³
Density = 0.15 g/cm³
Therefore, the density of the box is 0.15 g/cm³
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