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tankabanditka [31]
3 years ago
6

Explain how the loss of a plant, or producer, in an ecosystem can affect a secondary consumer

Physics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer with Explanation:

A food chain is a series of transmission of food and energy within an ecosystem. In a food chain the food and energy is transferred in the trophic levels. The trophic levels forms the hierarchy of feeding organisms in a food chain.

The producers come in the lowest trophic level. These are the organisms which can synthesize their own food by photosynthesis. They are the source of food and energy for a large diversity of animals and organisms of the other trophic levels.

The loss of plants, or producers from an ecosystem can reduce the population of primary consumers as they includes the herbivores. The decline in population of the primary consumers will reduce the population of secondary consumers which may include the carnivores.

vova2212 [387]3 years ago
3 0
When plants die they become food for the decomposer for example Lettuce, If all the Lettuce in someones field died the decomposer would get its nutriets and make the soil stronger, so if you plant more Lettuce and it survives the Consumer would get to eat the lettuce. Hope this helped! :)
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Ann [662]

i believ that the answer would be

the acceleration of B is 0.2

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2 years ago
Which example possesses mechanical potential energy?. A. a taut guitar string. B. an oscillating pendulum. C. a roller coaster r
NeTakaya
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7 0
3 years ago
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The same force is applied to two skateboards. One rolls across the room and the other moves a few feet and comes to a stop. Wher
igor_vitrenko [27]

The longer you spend reading and thinking about this question,
the more defective it appears.

-- In each case, the amount of work done is determined by the strength
of the force AND by  the distance the skateboard rolls <em><u>while you're still </u></em>
<em><u>applying the force</u>.   </em>Without some more or different information, the total
distance the skateboard rolls may or may not tell how much work was done
to it.<em>
</em>
-- We know that the forces are equal, but we don't know anything about
how far each one rolled <em>while the force continued</em>.  All we know is that
one force must have been removed.

-- If one skateboard moves a few feet and comes to a stop, then you
must have stopped pushing it at some time before it stopped, otherwise
it would have kept going. 

-- How far did that one roll while you were still pushing it ?

-- Did you also stop pushing the other skateboard at some point, or
did you stick with that one?

-- Did each skateboard both roll the same distance while you continued pushing it ?

I don't think we know enough about the experimental set-up and methods
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8 0
2 years ago
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A constant net torque is exerted on an object. Which of the following quantities for the object cannot be constant? (Select all
prohojiy [21]

Answer:

A. kinetic energy

B. angular velocity

E. angular position

Explanation:

The quantities that cannot be constant if a constant net torque is exerted on an objecta are:

A. Kinetic energy. If a torque is applied, the linear or angular speed will be changing at a rate proportional to the torque, so the kinetic energy will change too.

B. Angular velocity. It will change at a rate equal to the torque.

C. Angular position. If the angular velocity changes, the angular position will change.

3 0
3 years ago
A motorboat traveling 4 m/s, East encounters a current traveling 3.0 m/s, North. a) What is the resultant velocity of the motorb
Nostrana [21]

Explanation:

It is given that,

Velocity in East, v_1=4\ m/s

Velocity in North, v_2=3\ m/s

(a) The resultant velocity is given by :

v=\sqrt{4^2+3^2}=5\ m/s

(b) The width of the river is, d = 80 m

Let t is the time taken by the boat to travel shore to shore. So,

t=\dfrac{d}{v}

t=\dfrac{80\ m}{5\ m/s}

t = 16 seconds

(c) Let x is the distance covered by the boat to reach the opposite shore. So,

x=v_2\times t

x=3\ m/s\times 16\ s

x = 48 meters

Hence, this is the required solution.

4 0
3 years ago
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