Answer:
volumetric flow rate = ![0.0251 m^3/s](https://tex.z-dn.net/?f=0.0251%20m%5E3%2Fs)
Velocity in pipe section 1 = ![6.513m/s](https://tex.z-dn.net/?f=6.513m%2Fs)
velocity in pipe section 2 = 12.79 m/s
Explanation:
We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.
The density of water is = 997 kg/m³
density = mass/ volume
since we are given the mass, therefore, the volume will be mass/density
25/997 = ![0.0251 m^3/s](https://tex.z-dn.net/?f=0.0251%20m%5E3%2Fs)
volumetric flow rate = ![0.0251 m^3/s](https://tex.z-dn.net/?f=0.0251%20m%5E3%2Fs)
Average velocity calculations:
<em>Pipe section A:</em>
cross-sectional area =
![\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2](https://tex.z-dn.net/?f=%5Cpi%20%5Ctimes%20d%5E2%5C%5C%3D%5Cpi%20%5Ctimes%200.07%5E2%20%3D%203.85%5Ctimes10%5E%7B-3%7Dm%5E2)
mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)
![velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s](https://tex.z-dn.net/?f=velocity%20%3D%2025%2F%28997%20%5Ctimes%203.85%5Ctimes10%5E%7B-3%7D%29%20%3D%206.513m%2Fs)
<em>Pipe section B:</em>
cross-sectional area =
![\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2](https://tex.z-dn.net/?f=%5Cpi%20%5Ctimes%20d%5E2%5C%5C%3D%5Cpi%20%5Ctimes%200.05%5E2%3D%201.96%5Ctimes10%5E%7B-3%7Dm%5E2)
mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)
![velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s](https://tex.z-dn.net/?f=velocity%20%3D%2025%2F%28997%20%5Ctimes%201.96%5Ctimes10%5E%7B-3%7D%29%20%3D%2012.79m%2Fs)
It could be designed because if we had a small little pizza shop it would save our problems of going through all the trouble just for pizza
Answer:
c. an abrupt increase followed by a gradual decrease
Explanation:
At the headwater, the flow gradient starts high but then slowly decreases as the river moves downstream to its mouth.
Answer:
4140 steel contains 0.4% C having higher yield strength and ultimate strength than the 1045 steel contains 0.45% C
Explanation:
we have given 4140 steel contains 0.4% C
we know here that 4140 steel is low steel alloy , and it have low amount of chromium , manganese etc alloying element
and these elements which are present in 4140 steel they increase yield strength and ultimate strength of steel
while in 1045 steel contains 0.45 % c is plain carbon steel
and it do not contain any alloying element
so that 4140 steel contains 0.4% C having higher yield strength and ultimate strength than the 1045 steel contains 0.45% C
Answer:
#See solution for details.
Explanation:
#The commutative property of multiplication tells us that it doesn't matter in what order you multiply numbers. The formula for this property is a * b = b * a:
![40\times32\times10\times 25=320,000\\\\25\times10\times32\times 40=320,000\\\\10\times32\times25\times 40=320,000\\\\32\times25\times40\times 10=320,000](https://tex.z-dn.net/?f=40%5Ctimes32%5Ctimes10%5Ctimes%2025%3D320%2C000%5C%5C%5C%5C25%5Ctimes10%5Ctimes32%5Ctimes%2040%3D320%2C000%5C%5C%5C%5C10%5Ctimes32%5Ctimes25%5Ctimes%2040%3D320%2C000%5C%5C%5C%5C32%5Ctimes25%5Ctimes40%5Ctimes%2010%3D320%2C000)
Hence, the product of the four numbers remains 320,000 irrespective of their order.