1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nadya [2.5K]
3 years ago
12

Deaths due to lifestyle diseases have declined since the early 1900s. T F

Physics
1 answer:
zavuch27 [327]3 years ago
7 0

Answer:

<h2>False</h2>

Explanation:

Hope this helps! Please consider marking brainliest! Always remember, your smart and you got this! -Alycia :)

You might be interested in
Nasa’s goal is to help industry reduce emissions from aircraft by how much by 2050 compared to 2005?
lys-0071 [83]

Answer:

50%

Explanation:

Commercial aviation is responsible for 2% of global carbon emission. In the year 2009, the members of IATA (International Air Transport Association) had drawn a pledge to:

1. Halve the carbon emission due to aircraft by 2050, relative to emission of 2005

2. To make growth of industry carbon neutral by 2020

3. To cut CO₂ emission by 1.5% per year till 2020

To achieve these targets, a four pillar action plan was created.

8 0
3 years ago
An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, qE \times S + mg \times S = 0.5 \times mv^{2}

     1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight  and the above equation will be as follows.

   (1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2&#10;}

         v = sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}

           = 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0
3 years ago
An electron is emmited by an atomic nucleus in the process of...
Sliva [168]
I’m pretty sure it’s Radioactive decay
8 0
3 years ago
Read 2 more answers
A boat cruises 60 meters west in 10 seconds. What is its instantaneous velocity?
kari74 [83]

A - 6 meters a second ( 6m/s)

3 0
3 years ago
Read 2 more answers
Jumping up is work against gravity why​
lions [1.4K]

Answer:

gravitational force attract us towards the ground

Explanation:

6 0
3 years ago
Other questions:
  • Which is not a reason why the mass of an atom is expressed in atomic mass units rather than in grams?
    7·2 answers
  • What is a substance?
    14·1 answer
  • For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg
    11·1 answer
  • When applying Gauss' law for a capacitor containing a dielectric, which of the following statements is false? (Latter part of se
    12·1 answer
  • A snail crawls 300 cm in 1 hour. Calculate the snail's speed in each of the following units. A) cm/h B) cm/min C) m/h
    10·1 answer
  • The starting position is 0m. The starting velocity is 30m/s. Time is given as 2.5s. What is the final position of the object?
    7·1 answer
  • ¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!
    8·1 answer
  • You are hiking in Yellowstone National Park. A park ranger is speaking to students visiting a hot spring. Temperatures there can
    9·1 answer
  • Which statement places events during the Space Race in the correct order from the earliest to the most recent?
    12·2 answers
  • The gravitational field strength on earth is 10n/kg. find the weight of an object of mass 25kg​
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!