Biodiversity boosts ecosystem productivity where each species, no matter how small, all have an important role to play.A larger number of plant species means a greater variety of crops. Greater species diversity ensures natural sustainability for all life forms.
We are given that,

We need to find
when 
The equation that relates x and
can be written as,


Differentiating each side with respect to t, we get,



Replacing the value of the velocity


The value of
could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to



Search light is rotating at a rate of 0.96rad/s
I believe the percentage is between 15-20%. Stress is a well known factor that affects the performance of people.
Answer:
3.31m/s
Explanation:
Angular momentum for 3s is



Moment if inertia is


Angular speed
ω = L/I

The speed of each ball is
V = ωL

The third one sliding friction
Explanation: