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OverLord2011 [107]
3 years ago
9

Which statement BEST describes the condition of steady-state equilibrium? - System slowly adjusts to long-term changes in input

and output. - System inputs always exactly balance outputs so the system never change. - System inputs and outputs fluctuate around a stable average so the system does not move far from its average condition. - System inputs produce large, random fluctuations in output, forcing the system into a new state of equilibrium
Physics
1 answer:
krok68 [10]3 years ago
6 0

Answer:

System inputs and outputs fluctuate around a stable average so the system does not move far from its average condition.

Explanation:

Steady-state equilibrium can also be called dynamic equilibrium. The main difference between the two is the type of system we are considering. When a system is closed, and it attains equilibrium, there is no transfer of energy. In  the case of an open system, even if the system achieves equilibrium there will be some transfer of energy but it will not deviate far from it's equilibrium point, that is, it will be in a steady-state.

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tino4ka555 [31]

Angle, θ2 at which the light leaves mirror 2 is 56°

<u>Explanation:</u>

Given-

θ1 = 64°

So, α will also be 64°

According to the figure:

α + β = 90°

So,

β = 90° - α

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β + γ + 120° = 180°

γ = 180° - 120° - β

γ = 180° - 120° - 26°

γ = 34°

γ + δ = 90°

δ = 90° - γ

δ = 90° - 34°

δ = 56°

According to the law of reflection,

angle of incidence = angle of reflection

θ2 = δ = 56°

Therefore, angle θ2 at which the light leaves mirror 2 is 56°

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Explanation:

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Pete Zaria works on weekends at Barnaby's Pizza Parlor. His primary responsibility is to fill drink orders for customers. He fil
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Answer:

W_n_e_t=7.648512 \approx 7.6J

K.E=0.8J

v=0.7844645406 \approx 0.78m/s

Explanation:

From the question we are told that

Mass of pitcher   M= 2.6kg

Force on pitcher f=8.8N

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Coefficient of friction \mu=0.28

a)Generally frictional force is mathematically given by

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F=0.28*2.6*9.8

F=7.1344N

Generally work done on the pitcher is mathematically given as

W_n_e_t=W_f+W_F

W_f=8.8*0.48=>4.224N\\W_F=7.1344*0.48=>3.424512N

W_n_e_t=4.224-3.424512

W_n_e_t=0.799488\approx 0.8J

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K.E= W_n_e_t

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K.E=0.8J

c)Generally the equation for kinetic energy is mathematically represented by

K.E=1/2mv^2

0.8=1/2mv^2

Velocity as subject

v=\sqrt{\frac{K.E*2}{m} }

v=\sqrt{\frac{0.8*2}{2.6} }

v=0.7844645406 \approx 0.78m/s

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