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laiz [17]
2 years ago
11

A hunter is aiming horizontally at a monkey who is sitting in a tree. The monkey is so terrified when it sees the gun that it fa

lls off the tree. At that very instant, the hunter pulls the trigger. What will happen?
a. The bullet will hit the monkey because both the monkey and the bullet are falling downward at the same rate due to gravity.
b. The bullet will miss the monkey because the monkey falls down while the bullet speeds straightforward.
c. It depends on how far the hunter is from the monkey.
d. The bullet will miss the monkey because although both the monkey and the bullet are falling downward due to gravity, the monkey is falling faster.
Physics
2 answers:
vekshin12 years ago
8 0

The answer to the question is a

Vladimir79 [104]2 years ago
5 0

a. The bullet will hit the monkey because both the monkey and the bullet are falling downward at the same rate due to gravity.

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The explanation is in the attachment.

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Answer:

E_y=1175510.2\ N.C^{-1}

The Magnitude of electric field is in the upward direction as shown directly towards the charge q_1.

Explanation:

Given:

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<u>Distance of the center from each corners</u>=\frac{1}{2} \times diagonals

diagonal=\sqrt{52.5^2+52.5^2}

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Now, electric field due to charges is given as:

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E_1=9\times 10^9\times \frac{45\times 10^{-6}}{0.3712^2}

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<u>Force by each of the charges at the remaining corners:</u>

E_2=E_3=E_4=9\times 10^9\times \frac{27\times 10^{-6}}{0.3712^2}

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<u> Now, net electric field in the vertical direction:</u>

E_y=E_1-E_4

E_y=1175510.2\ N.C^{-1}

<u>Now, net electric field in the horizontal direction:</u>

E_y=E_2-E_3

E_y=0\ N.C^{-1}

So the Magnitude of electric field is in the upward direction as shown directly towards the charge q_1.

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