The order of components in a typical flame atomic absorption spectrometer is hollow cathode lamp--flame--monochromator--detector
<u>Explanation:</u>
- The hollow cathode lamp practices a cathode created of the element of interest with a low internal pressure of inert gas.
- Remove scattered light of other wavelengths from the flame. AAS flame includes aiming at first the fuel than the oxidant and then lighting the flame with the instrument's auto-ignition system. Applying flame Ddtroy any analyte ions and breakdown complexes.
- The process of the monochromator is to divide analytical lines photons moving through the flame
- Photomultiplier tube (PMT) as the detector the PMT determines the intensity of photons of the analytical line exiting the monochromator.
Thermosoftening plastics melt when they are heated.This means that they can be recycled , which involves melting them before making a new product. Thermosoftening plastics do not have covalent bonds between neighbouring polymer molecules, so the molecules can move over each other when heated and the plastic melts.
Ionization energy is the energy needed to remove one electron from an atom in the gaseous state.
Ionization energy (IE) is the force needed to ionize a neutral atom or cation when it is in its gaseous state. Ionization potential is another name for IE. Ionization energy is conceptually defined as an element's affinity for its outermost electron (an electron it already has in its valence shell).
The least amount of energy needed to ionize an atom is needed to remove an electron from its ground state. Across the periodic table, there is a regular increase in ionization energy from top to bottom and left to right.
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The molecular weight of SOCL2 is 118.97 g/mol
Answer:
The volume of the container would be 1507 L
Explanation:
These question can be solved in two different ways:
Let's do the short road.
We know that 1 mol of anything at STP conditions occupies 22.4 L
By a rule of three:
1 mol contains 22.4L at STP
Then, 67.3 mol of gas would be contained in (67.3 . 22.4) /1 = 1507.5 L
We assume CO₂ as an Ideal Gas, so we can apply P . V = n . R . T
At STP, T is 273.15K and P = 1 atm. We replace:
1 atm . V = 67.3 mol . 0.082 . 273.15K
V = (67.3 mol . 0.082 . 273.15K) / 1 atm → 1507 L